2016年7月18日 · sqrt3/2 There are 2 ways, that don't need calculator a. Trig table of special arc --> cos (pi/6) = sqrt3/2 b. Use triangle trigonometry Consider a right triangle ABH that is half of …

2016年9月29日 · cos(pi/6)=sqrt(3)/2 (see image below of bisected equilateral triangle) cos = "adjacent"/"hypothenuse"

2018年4月13日 · How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question

2015年5月15日 · In opposition, the ordinate (the y position on the graph)= the sine value =1/2 with an angle of pi/6 and =-1/2 with an angle of -pi/6. Trigonometry Science

Since #pi/6# is 30 degrees on the unit circle, draw a triangle on the where 30 degrees is the reference angle. Since cosine is #a/h#, the respective sides are #sqrt3# being the adjacent …

2016年5月7日 · We can subtract #2pi# from #(19pi)/6# and still have the same value of cosine--the angles would be in the same location in the unit circle.

2018年7月15日 · (sqrt3+1)/2 For problems like these, it helps to memorize the Unit Circle. On the Unit Circle, the coordinates for pi/6 (30^@) are (sqrt3/2,1/2) Where the x-coordinate is the …

2016年4月11日 · and # sin(pi/3) = (sqrt3)/2 , sin(pi/6) = 1/2 # substituting these values into the right side of the expansion. #= [1/2xx(sqrt3)/2] +[ (sqrt3)/2xx 1/2] = 1/4 sqrt3 + 1/4 sqrt3 = 1/2 …

2016年4月7日 · Trig table and trig unit circle --> #cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) =# #= cos (-pi/6) = cos (pi/6) = sqrt3/2#

2015年10月25日 · Find exact value of cos ((5pi)/6) Ans: sqrt3/2 On the trig unit circle, cos ((5pi)/6) = cos (- pi/6 + pi) = - cos (pi/6) Trig Table of Special Arcs gives --> cos ...