2017年1月26日 · see below cot x sec x = cos x/ sinx * 1/cos x =cancel cos x/ sinx * 1/cancelcos x =1/sinx =csc x

2015年10月26日 · How do you use use quotient identities to explain why the tangent and cotangent function have

1 cot(x) = 1/(tan(x)) = (cos(x))/(sin(x)) sec(x) = 1/(cos(x)) csc(x) = 1/sin(x) implies (cot(x)sec(x))/csc(x) = (cos(x)/(sin(x))*1/(cos(x)))/(1/(sin(x))) = (sin(x ...

2016年10月3日 · How do you solve #cotxsecx+cotx=0# and find all general solutions? Trigonometry Trigonometric Identities and Equations Solving Trigonometric Equations 1 Answer

2015年11月28日 · Given: #tan x+ cot x= sec x *cscx# Start on the right hand side, change it to #sinx#; #cosx#. #sinx/cosx + cosx/sinx = sec x *csc x#

2018年6月12日 · We need. #tanx=sinx/cosx# #cotx=cosx/sinx# #secx=1/cosx# #sin^2x+cos^2x=1# The expression is #(tanx+cotx)/secx=(sinx/cosx+cosx/sinx)/(1/cosx)#

2017年1月17日 · Left Hand Side: #sec^2x cot x - cot x=cotx(sec^2x-1)# Use identity: #1+tan^2x=sec^2x# #=cotxtan^2x# #=cosx/sinx * sin^2x/cos^2x#

2018年2月20日 · We want to verify. #cot(x)sec(x)/csc(x)=1# Use the definitions of cotangent, secant and cosecant . #cot(x)=cos(x)/sin(x)#

2018年5月13日 · See below We will use the following identities secx:=1/cosx cotx=cosx/sinx cscx=1/sinx Proof secxcotx=1/cancelcosxcancelcosx/sinx=1/sinx=cscx color(white ...

2016年5月21日 · On the left side, #(1+cscx)/(cotx+cosx)# Rewrite #cscx# and #cotx# in terms of #sinx# and #cosx#. #=(1+color(blue)(1/(sinx)))/(color(purple)((cosx)/(sinx))+cosx)#