y = log tanx differentiate wrt x dy/dx = 1/tanx .d(tanx)/dx = 1/tanx .sec²x = sec²x/tanx

2017年8月18日 · $\begingroup$ When you substitute in dtan(x) into a problem, it gets rid of the dx which indicates which variable to integrate with respect to. $\endgroup$ – Bob Shannon Commented May 7, 2013 at 18:14

#int sec^5x dx = tanxsec^3x + 3int sec^3x dx -3 int sec^5x dx# The integral now appears on both sides of the equation and we can solve for it obtaining a reduction formula: #int sec^5x dx = 1/4(tanxsec^3x + 3int sec^3x dx)#

2016年3月28日 · If we rewrite $\\displaystyle \\frac {d} {dx} \\cot(x)$ as $\\displaystyle \\frac {d} {dx} \\frac {1} {\\tan(x)}$ and then apply the quotient rule, we get to ...

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dy/dx = d/dx(log(secx) dy/dx = 1/secx × secx × tanx dy/dx = tanx. anshika. Last Activity: 3 Years ago .

In a couple of trig identities, esp to do with integrals and derivatives, you see a relationship between tan(x) and sec(x).

2017年5月4日 · However, there is a nice geometric proof that $\frac {d}{dx} \tan x = \sec^2 x$ that is worth knowing. In the figure we have two right triangles. The base is 1.

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Here is a straightforward way of finding the derivative manipulating only sines and cosines: $$ \frac{d}{dx} \left[ \frac{\sec(x)}{1+\tan(x)} \right] \\ = \frac{d}{dx ...