What is the nth derivative of f (x) = x e^ (2x)? | Socratic
2015年4月13日 · We can write the derivative of this function in a ricorsive way. Ricorsive way means that also in the definition there is the concept of derivate! y^ ( (1))=1*e^ (2x)+x*e^ …
What is the derivative of sqrt(e^(2x) +e^(-2x))? | Socratic
2016年2月18日 · 1/2 (e^ (2x)+e^ (-2x))^ (-1/2)* (2e^ (2x)-2e^ (-2x)) We may apply the power rule to obtain : d/dxsqrt (e^ (2x)+e^ (-2x))=d/dx (e^ (2x)+e^ (-2x))^ (1/2) =1/2 (e^ (2x ...
How do you find the fourth derivative of - Socratic
2016年11月29日 · You can use the chain rule to find the first derivative of e2x and differentiate iteratively
How to find formula for nth derivative of - Socratic
2017年7月5日 · How to find formula for nth derivative of f (x) = e2x(x2 − 3x + 2)?
How do you find the derivative of the function - Socratic
2018年5月27日 · How do you find the derivative of the function y = cos(1 − e2x 1 + e2x)?
What is the derivative of y= ln (1 + e^ (2x))? | Socratic
2015年12月26日 · The derivative is d ln(1 + e2x) dx = (1 + e2x)' 1 +e2x = 2 ⋅ e2x 1 +e2x Finally dy dx = 2 ⋅ e2x 1 +e2x
How do you find the derivative of - e^ (2x))? | Socratic
2015年4月28日 · You can use the Chain Rule to derive ln first (as it is) and then multiply by the derivative of the argument as: y' = 1 1 + e2x ⋅ 2e2x = 2e2x 1 +e2x
How do you differentiate y = e^ (2x) ln x? | Socratic
2016年9月28日 · (dy)/ (dx)=e^ (2x) (2lnx+1/x) To differentiate y=e^ (2x)lnx, we use product rule according to which if f (x)=g (x)xxh (x) (df)/ (dx)=g (x)xx (dh)/ (dx)+ (dg)/ (dx)xxh ...
How do you find the derivative of tanh(1+e^(2x))? | Socratic
2015年4月16日 · Applying chain rule, the derivative would be 2e^ (2x) sech^2 (1+e^ (2x))
How do you find the derivative of the function: - Socratic
2016年1月20日 · How do you find the derivative of the function: y = arccos[e2x]?