2016年2月21日 · Initializing dynamically allocated arrays. If you want to initialize a dynamically allocated array to 0, the syntax is quite simple: int *array = new int[length](); Prior to C++11, there was no easy way to initialize a dynamic array to a non …

2016年12月8日 · Instead of having arrayOfAs be an array of A objects, have it be an array of A* pointers. I would think this is just some beginners thing where there's a syntax that actually works when attempting to dynamically allocate an array of things that have internal dynamic allocation.

If you want to grow the array dynamically, you should use malloc() to dynamically allocate some fixed amount of memory, and then use realloc() whenever you run out. A common technique is to use an exponential growth function such that you allocate some small fixed amount and then make the array grow by duplicating the allocated amount.

2011年10月4日 · Dynamically allocated array of dynamically allocated strings. 0. Allocate memory to array of strings in C. 3.

2009年5月27日 · Of course, you can also declare the array as int* array[50] and skip the first malloc, but the second set is needed in order to dynamically allocate the required storage. It is possible to hack a way to allocate it in a single step, but it would require a custom lookup function, but writing that in such a way that it will always work can be ...

2017年1月25日 · There is no portable way in C++ to get the size of a dynamically allocated array from the raw pointer. Under MSVC and WIN32 you can get the size of the allocated block with the _msize(void*) function.

2015年10月27日 · class Node { int key; Node**Nptr; public: Node(int maxsize,int k); }; Node::Node(int maxsize,int k) { //here i want to dynamically allocate the array of pointers of maxsize key=k; } Please tell me how I can dynamically allocate an array of pointers in the constructor -- the size of this array would be maxsize.

Yes, please use array[position], even if the parameter type is int *array.The alternative you gave (*array[position]) is actually invalid in this case since the [] operator takes precedence over the * operator, making it equivalent to *(array[position]) which is trying to dereference the value of a[position], not it's address.

2017年11月17日 · Third, the copy constructor copies the pointer. When the first object goes out of scope its destructor deletes the array; when the copy goes out of scope its destructor also deletes the array. Again, not good. The copy constructor has to make a copy of the array. In order to do that the class needs to also store the number of elements the array.

2012年9月25日 · I basically want to dynamically allocate an array of pointers. ... array elements which itself is a ...