Aug 10, 2016 · e^ (x+2) Using the color (blue)"law of exponents" color (orange)"Reminder " color (red) (|bar (ul (color (white) (a/a)color (black) (a^mxxa^n=a^ (m+n))color (white ...

Mar 30, 2015 · Basically "E" simply replaces "xx10^" in the standard scientific notation. So, 2.24xx10^4 would be written as 2.24E4 or sometimes 2.24E+4

Jul 13, 2016 · We can use the law of exponents to simplify this expression. Note that an ⋅ am = am+n In this case, we do the same: e−2 ⋅ e6 = e−2+6 = e4 If you like, you can think of e−2 as 1 e2. Alternatively you can write e6 e2 = e4

Jun 5, 2018 · L=lim_ (x->oo)x^3*e^ (-x^2)=0 We want to solve L=lim_ (x->oo)x^3*e^ (-x^2)=lim_ (x->oo)x^3/e^ (x^2) Which is an indeterminate form oo/oo So we can apply L'Hôpital's ...

Jun 2, 2015 · We know x approches +prop Thus x² also approches +prop, but faster Thus x-x² approches -prop And we know that when y approches -prop, e^y approches 0 Thus lim(e^(x-x²))=0

Jul 20, 2016 · Equation of the tangent at x=0 is y=1 y= ln(x^2+e) dy/dx = 1/(x^2+e) * 2x Therefore slope of the tangent to y at x=0 is: m = 1/e * 0 = 0 Equation of the tangent is given by: y=mx+c Where m is the slope and c is constant Since m = 0 -> y = c In this case From original function: y(0) = ln(0+e) = ln(e) = 1 Therefore the tangent touches y at the point (0,1) Hence c=1 …

Oct 26, 2017 · Use the rule for finding the derivative of the product of two functions. if y = f (x)g(x), then dy dx = f '(x)g(x) + f (x)g'(x) Here, f (x) = ex, so f '(x) = ex g(x) = x2 − 3, so g'(x) = 2x Put 'em all together: f '(x)g(x) + f (x)g'(x) = ex(x2 − 3) + ex2x ...Wolfram tells me I need to factor: ex(x2 + 2x − 3) GOOD LUCK

Mar 8, 2015 · I think it should be zero; If you do the limit directly you should getoo/oo; If you apply the de l'Hospital Rule (derive numerator and denominator and then do the limit); lim_ (x->oo) (1/ (2xe^ (x^2)))=0

Apr 1, 2018 · d/dxe^ (x^2)=2xe^ (x^2) In general, when applying the Chain Rule to the exponential, d/dxe^u=e^u (du)/dx. Here, u=x^2, so d/dxe^ (x^2)=e^ (x^2)d/dxx^2 d/dxe^ (x^2)=2xe^ (x^2)

Sep 26, 2016 · Remember that e2 is a constant. (It is about 2.72 which is about 7.3)