2010年7月4日 · Now, every positive number y is the result of e raised to some power (it's not a proof, but looking at the graph of e^x will probably convince you of this). This power is called …

2008年6月5日 · What lead them to use e and the natural log of 2 in the decay formula? A much simpler (to me at least) method would is: N=No*.5^(time/half life)

2015年2月4日 · sinh(ln2+ ipi/3) so I have a general formula of sinh z= (e^z - e^-z)/2 so I obtained the following sinh= (e^(ln2 + ipi/3) - e^-(ln2 + ipi/3))/2 sinh= (e^(ln2) e^(ipi/3) - e^(-ln2) …

2010年1月3日 · e^(lnx)^2=e^(ln2)^x this trivializes and is simple to solve. Yes so you have [itex]x^2=2^x[/itex] but really, this isn't as simple to solve as you claim. It's just that we are …

2009年12月27日 · What exponential function -DO- you know how to integrate? Hint: [tex]\frac{d}{dx}e^x=e^x[/tex] You can use that relationship to find the integral of any base …

2007年9月18日 · However, the mistake in the solution process was taking the exponential of the entire equation instead of using the property e^{a+b} = e^ae^b. The correct approach is to use …

2011年8月10日 · Homework Statement find the integral from 0 to ln2 of (e^x-1)/(e^x+1) Homework Equations The Attempt at a Solution I really didn't know what to do, but the book …

2010年4月17日 · I realize if you replace k with ln2, you get e^(ln2) = 2 = 1 + k/1! + (k^2)/2!...So the series approaches 2. As a last resort I will go caveman style and add up all terms from 0-10. …

2009年4月15日 · Homework Statement The initial activity of I_131 is 0.74MBq. The half time of I_131 is 8 days. How large is the activity after two days?Homework Equations A = A_0 e^{ …

2014年4月16日 · Homework Statement The practical limit to ages that can be determined by radiocarbon dating is about 41000-yr-old sample, what percentage of the original 6 12 C …