Nov 11, 2022 · eax, ebx, ecx and so on are actually registers, which can be seen as "hardware" variables, somewhat similar to higher level-language's variables. Registers can be used in your software directly with instructions such as mov, add or cmp.

Nov 25, 2016 · EAX: "Extended Accumulator" - used for arithmetic and logical operations, as well as for storing return values from functions. EBX: "Extended Base" - often used as a pointer to data in the data segment of memory. ECX: "Extended Counter" - often used for loop and string operations, as well as for storing function arguments.

Sep 29, 2020 · MOV sets EAX = the value from memory at that address. Your re-phrasing of the existing answer isn't adding anything new, and is actually less clear because you're mis-using "address" to mean "memory at that address", which is …

In your example the address calculation is very simple, because it just adds a offset to ebx and stores the result in eax: eax = ebx + 0x10. lea can do a lot more. It can add registers, multiply registers with the constants 2, 4 and 8 for address calculations of words, integers and doubles. It can also add an offset.

May 21, 2009 · EAX: "Extended Accumulator" - used for arithmetic and logical operations, as well as for storing return values from functions. EBX: "Extended Base" - often used as a pointer to data in the data segment of memory. ECX: "Extended Counter" - often used for loop and string operations, as well as for storing function arguments.

Feb 12, 2025 · I am new to this EAX DB, just found this thread less than 3 hours ago, and have been trying to read as much as i can, and tried to set up the EAX DB myself in my MT4. But I can't seem to make it works. I don't even know If I'm setting up everything right. I've activated the force history script before running the EAX. my question are: 1.

Dec 2, 2015 · Latest EAX update (on a fresh setup install prerequisites first) Inserted Code DBMASMEAX007a3.bundle3 rev.update.013.7.5 (20220615): …expiring in 2023.12.31 23:59:59 GMT !

Aug 21, 2019 · lea eax, DWORD PTR [eax + eax*4] loads eax with the value eax + eax*4, which is c + c*4, thus the desired return value of the function. I'd recommend, though, doing an interwebs search on x86 lea instruction as you'll find lots of information on what it does and why.

In this case, it's doing a simple numeric subtraction: leal -4(%ebp), %eax just assigns to the %eax register the value of %ebp - 4. It's equivalent to a single sub instruction, except a sub requires the destination to be the same as one of the sources.

The assembly output makes sense to me (mostly) except for the line xorl %eax, %eax. From googling, I gather that the purpose of this is simply to set %eax to zero, which in this case corresponds to my iterator long i;. However, unless I am mistaken, %eax is a 32-bit register.