In a hydrogen oxygen fuel cell, electricity is produced. In this process H 2 (g) is oxidised at anode and O 2 (g) reduced at cathode. Given : Cathode: O 2 (g) + 2 H 2 O (l) + 4 e − → 4 O H − (a q) Anode : H 2 (g) + 2 O H − (a q) → 2 H 2 O (l) + 2 e − 4.48 L of H 2 at 1 atm and 273 K is oxidised in 9650 sec. The mass of water ...

When Na2SO4 dissociates in water, it forms Na+ and SO4(2-) ions. At the anode, oxidation reactions occur, which involves the loss of electrons. At the cathode, reduction reactions take place, where electrons are gained. The possible anode reactions are the processes that involve the production of electrons.

Anode → 2H 2 O → 4H + + O 2 + 4e- In cathode, the product the reduction is OH - , which is base becomes purple after being added by phenolphthalein and in anode, the product of oxidation is H+ is acid.

Nov 28, 2016 · The three aqueous solutions (NaBr, PbI2, Na2SO4) undergo electrolysis to yield different half-reactions at the anode and cathode. In the electrolysis of aqueous NaBr, the anode reaction is 2Br- -> Br2 + 2e-, while the cathode reaction is 2H2O + 2e- -> H2 + 2OH-.

in the electrolysis of aqueous solution of Na2SO4, what reactions occur at the anode and the cathode. explain Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

In the electrolysis of an aqueous solution of Na 2 SO 4, what reactions occur at the anode and the cathode (assuming standard conditions)? (Use the lowest possible coefficients. Omit states-of-matter from your answer.)

Jan 14, 2025 · Oxidation reaction: 2H 2 O (l) → 4H + (aq) + O 2 (g) + 4e- Reduction reaction: 2H 2 O (l) + 2e-→ H 2 (g) + 2OH-(aq) At the cathode, either the metal ion M + or water can be reduced. At the anode, either the anion A-or water can be oxidized. Which species is discharged depends on three things: The relative values of E θ. The concentration ...

Electrical current is applied to water containing Na2SO4 as an electrolyte. The water is converted into gaseous H2 and O2 at the electrodes. ANODE HALF REACTION: 2H 2 O —> 4H + + O 2 + 4e -

In the electrolysis of N a 2 S O 4 solution using inert electrode. a) the anodic reaction is. 2 H 2 O → O 2 (g) + 4 e − + 4 H + b) H 2 (g) and O 2 (g) is produced in a molar ratio of 2:1. c) 23 grams of sodium is produced at the cathode. d) the cathode reaction is N a + + e − → N a

Aqueous N a 2 S O 4 solution on electrolysis produces O 2 gas at anode and H 2 gas at cathode. At anode: 2 H 2 O (l) → O 2 (g) + 4 H + (a q) + 4 e − At cathode: H 2 O (l) + e − → 1 2 H 2 (g) + O H − (a q)