2018年6月26日 · Shown below find two points on the graph, then join them up. When x = -1 => y = 2*(-1) = -2 x = 1 => y = 2*(1) = 2 Hence we get two point (-1,-2) " and " (1,2) Now plot the points on a graph Now join then up:

"If f(x) = 2x, describe the transformation of the curve for g(x) = -2 x-2 I desparetely need help with this thank you" I assume you mean the line rather than the 'curve,' as both f(x) and g(x) are linear. For the record, here is a graph of both: F(x)=2x G(x)=-2x-2 What the question is basically asking is 'How does G differ from F?'

2018年5月18日 · Initially we may naively think that the graph of y=f(2x) is a stretch of y=f(x). However, we can show that in fact it is a compression, if we construct a table for a generic function for some (arbitrary) integer values of the domain: {: (x,0,1,2,3,4,5,6), (f(x),color(red)(f(0)),f(1),color(green)(f(2)),f(3),color(blue)(f(4)),f(5),color(purple)(f(6))), (,,,,,), (f(2x),color(red)(f(0)),color ...

2018年3月3日 · 1) change notation #f(x) = # to y = So, y = 2x + 7. 2) Exchange the x & y variables. Note this is what accomplishes that reflection across the line y = x. So, x = 2y + 7. 3) Since x is the dependent variable and y is the independent variable and it is always a zillion times easier to solve a problem in y = form, solve the equation for y.

You can put this solution on YOUR website! Hi, f(x)=2x^2+4x+5 y=intercept Pt(0,5) the vertex form of a parabola, where(h,k) is the vertex

2015年5月25日 · Simle. You substitute x for x+2: f(x+2)=2(x+2)+1 f(x+2)=2x+4+1 f(x+2)=2x+5 You do the same as you'd do if it was asking the value for your function when x equals some number.

The gradient/slope of a function of f(x) = (2x-b)^a is f'(x) = 24x^2-24x+6, find the constant a and b. I'm a confused on how to start on this. ~~~~~ The wording of the problem means that the derivative of the function f(x) = (2x-b)^a is the polynomial of degree 2, f'(x) = 24x^2 - 24x + 6. It means that f(x) is a polynomial of degree 3; hence, a= 3.

2015年9月30日 · Write y= 2x-5 and now interchange x and y. It becomes x= 2y-5. Answer link. Alan P.

Question 880455: Find the derivative of f(x)= 2x^2+3x-5 using the definition of the derivative (DO NOT USE the rules of differentiation). Answer by ewatrrr(24785) ( Show Source ): You can put this solution on YOUR website!

If f(x) = 2x-4, find f^-1(x)-----y = 2x-4 To find the inverse: interchange x and y to get: x = 2y-4