Rewrite the function as an equation. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... Graph the line using the slope and the y-intercept, or the points.

Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.

How do you solve the differential equation given f ′(x) =4x , f (0)=6? \displaystyle {y}= {f { {\left ( {x}\right)}}}= {2} {x}^ { {2}}+ {6} Explanation: Substitute \displaystyle\frac { {\left. {d} {y}\right.}} { {\left. {d} {x}\right.}} for \displaystyle {f}' {\left ( {x}\right)} ... y …

A function basically relates an input to an output, there’s an input, a relationship and an output. For every input... AI may present inaccurate or offensive content that does not represent Symbolab's views.

Verify if f −1(x) = x 4 f - 1 (x) = x 4 is the inverse of f (x) = 4x f (x) = 4 x. Tap for more steps... Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

通过选择恰当的 g(x) 和 h(x) ，我们能构造出一系列 f(x) ，使得 f(f(x))=x 在各自的定义域上成立. 下面列举一些常见的 f(x) . 令 g(x)=1-x ， h(x)=x^3 ，有 f(x)=(1-x^3)^{\frac 1 3}

f(x)=2x+3和f(x)=−2x−9f(x)是一次函数，设函数f(x)=kx+b(k≠0)，则：f(f(x))=k(kx+b)+b=k2x+kb+b∵f(f(x))=4x+9，可得：k2x+kb+b=4x+9，即{k2=4kb+b=9，解得：{k=2b=3或{k=−2b=−9，∴f(x)的函数关系式为f(x)=2x+3和f(x)=−2x−9．故答案 …

2011年8月30日 · f（4x）表示自变量是4x，图像是f（x)的图像压缩4倍，f(-x)表示自变量是-x，在函数里可以把它们看成是复合函数，设y=4x则f（4x）=f（y），y（x）=4x，即f是y的函数，y是x的函数，在初中学过二次函数，内容就有平移和旋转，也可以看成是复合函数

利用待定系数法求解该函数的解析式是解决本题的关键．结合着复合函数表达式的求解，根据多项式相等即对应各项的系数相等得出关于一次项系数和常数项的方程组，通过方程思想求解出该函数的解析式．. 本题考点：函数解析式的求解及常用方法．. 考点点评：本题考查函数解析式的求解，考查确定函数解析式的待定系数法．学生只要设出一次函数的解析式的形式，寻找关于系数的方程或方程组，通过求解方程是不难求出该函数的解析式的．属于函数中的基本题型．. 解析看 …