2017年10月19日 · The graph is of general shape #uu# as the #x^2# term is positive Given: #y=ax^2+bx+c color(white)("d")->color(white)("d")x^2+x+1#

2014年9月13日 · The graph of f(x)=x^2 is called a "Parabola." It looks like this: One of the ways to graph this is to use plug in a few x-values and get an idea of the shape. Since the x values keep getting squared, there is an exponential increase on either side of the y-axis. You can see this by plugging in a few values: When x=0, f(x)=0 x=1, f(x)=1^2=1 x=2,f(x)=2^2=4 x=3, f(x)=3^2=9 x=4, f(x)=4^2=16 The ...

2016年11月28日 · How do you find the derivative of #f(x)=1/x^2# using the limit process? Calculus Derivatives Limit Definition of Derivative . 1 Answer

2018年7月2日 · See answer below Given: f(x) = x^2 + 1 You can use point plotting. Select any x value and then calculate the y value and plot. ul(" "x" "| " "y" ") ""-4" "|" "17 ""-2" "|" "5 " "0" "|" "1 " "2" "|" "5 " "4" "|" "17 or you can realize that x^2 + 1 is a vertical shift up 1 of the parent function f(x) = x^2 or you can just graph the function using a graphing calculator. TI …

Multiply both sides of this equation by -1 to get: x^2 = 1 Take the square root of both sides of this equation to get: x = +/- 1 Those should be the x-axis crossing points. You could also have factored the equation of -x^2 + 1 = 0 to get: (-x+1) * (x+1) = 0 When either of these factors = 0, the equation is grue, so you set each of the factors ...

2018年5月15日 · f(g(x))=1/x^2+1 f(x)=x^2+1 g(x)=1/x In order to find f(g(x)), we must substitute g(x) in for x for the equation f(x). (1/x)^2+1 Now, all we need to do is simplify to find the final answer. 1/x^2+1

2018年3月4日 · (f@g@h)(x) = 4x^2-8x+5 Given: { (f(x) = x^2+1), (g(x) = 2x), (h(x) = x-1) :} One way of thinking about these function compositions is to go back and forth between the symbols and verbal descriptions of what the functions do. In our example: f takes the square of a number and adds 1 g doubles a number h subtracts 1 from a number So a verbal description of the composed f@g@h as a sequence of ...

f(x) = x^2 + 6x − 1 State the vertex and axis of symmetry of the graph of the function. We want to get it in the form where the vertex is (h,k) and the axis of symmetry is the vertical line whose equation is x=h.

2016年3月23日 · Let y = f(x) and solve for x. We find that there is no inverse function unless the domain of f(x) is restricted. Suppose f(x) = x^2-1 To attempt to find an inverse function, let y = f(x) and solve for x in terms of y... y = x^2-1 Add 1 to both sides to get: y + 1 = x^2 Transpose and take square root of both sides, allowing for either sign: x …

2016年11月25日 · lim_(x rarr 1)(x^2-1)/(x-1) = 2 Let f(x) = (x^2-1)/(x-1) then f(x) is defined everywhere except at x=1, however when we evaluate the limit we are not interested in ...