2017年7月19日 · Fe_2O_3+3C+Deltararr2Fe+3CO And this is a redox equation in which carbon (as coke) is oxidized to "carbon monoxide".....and "ferric oxide" is reduced to metallic iron.

2015年11月2日 · 4Fe + 3O_2 rarr 2Fe_2O_3 Step 1: Tally the number of atoms based on subscript. Fe + O_2 rarr Fe_2O_3 (unbalanced) left side: Fe = 1; O = 2 right side: Fe = 2; O = 3 Step 2: Start balancing the simple molecules first, in this case the O_2 Fe + color (green) 3O_2 rarr Fe_2O_3 left side: Fe = 1; O = 2 x color (green) 3 = 6 right side: Fe = 2; O = 3 Since there …

2016年4月25日 · Find the number of moles and molar mass for 2Fe, then determine the number of moles for 3CO Assume that: n = number of moles m = mass of substance M = molar mass (equivalent to atomic weight in the periodic table) n = m -: M The mass (m) of Fe is found. Your next step is to find the molar mass (M) of Fe. The molar mass of Fe is 55.9 g/mol. To find the …

2017年12月21日 · 12 Fe_2O_3 (s)+C (s)rarrFe (s)+CO_2 (g) Number of iron (Fe) atoms: 2 on the LHS, 1 on the RHS. Number of carbon (C) atoms: 1 on the LHS, 1 on the RHS. Number of oxygen (O) atoms: 3 on the LHS, 2 on the RHS. Since we have an odd number of oxygens, we should probably balance that first. Multiply by 2: 2Fe_2O_3 (s)+C (s)rarrFe (s)+CO_2 (g) Let's …

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2017年8月12日 · For "Fe"_2"O"_3(s) + 3"CO"(g) -> 2"Fe"(s) + 3"CO"_2(g) you should get -"23.47 kJ/mol", if you use my numbers. Go look up numbers from your own book and try again... see what you get, and verify mine is correct. Well, when you manage to search your appendix for the substances in... "Fe"_2"O"_3(s) + 3"CO"(g) -> 2"Fe"(s) + 3"CO"_2(g) ...and you manage to fix …

2016年8月19日 · Approx. 15*g of metal. "Moles of iron oxide, " Fe_2O_3 = (21.6*g)/(159.69*g*mol) = 0.135*mol with respect to the oxide. But by the composition of the oxide, there are thus 2xx0.135*molxx55.8*g*mol^-1 "iron metal" = ??g. An extraordinary percentage of our budgets goes into rust prevention; "iron(III) oxide" is only part of the redox …

2018年4月29日 · Consider the reaction when you bathe ferric oxide in oxalic acid, Fe_2O_3 + 6H_2C_2O_4 to 2Fe(C_2O_4)_3^(3-) +3H_2O + 6H^(+) The "rust" is the ferric oxide on the left side of your equation. An easy approximation to make for this relatively trivial question is that the given molar quantity of oxalic acid will "remove" a stoichiometrically ...

2017年9月20日 · If 14.6 mol of iron(III) oxide and 17.5 mol of carbon react, what is the maximum number of moles of iton that can be recovered from the reaction? 2 Fe2O3(s) + 3 C(s) → 4 Fe (s) + 3 CO2(g)