There are two ways to solve this problem: one way is Algebra, and another way is Calculus. Algebra way The range is the set of real values t such that 2x + = t for some x. In other words, the range is the set of real numbers t such that the quadratic equation 2x^2 + 3 = tx, or 2x^2 - tx + 3 = 0 has real solutions for x.

Question 954425: if f (x)=3x^2 and g (x)= 4x^3+1, what degree of (f o g) (x)? Answer by Alan3354 (69443) (Show Source):

The domain of f is all real numbers (since it is a polynomial), hence the value of g (x) is not restricted in any way. However, the domain of g is all real numbers except 13 and so the domain of the composite must be similarly restricted.

Question 612563: Suppose f (x) = x2 + 6x - 91 and g (x) = . At which of these points does the function (fxg) (x) have a hole? Answer by solver91311 (24713) (Show Source):

Here is how I thought it would be done: f (g (5)) = log (base 2) (2 (5^2) + 14) = log (2, 64) = 2^x =64 x = 6 Is this right? ---------------------------------- fog (x) means f [g (x)] ---- Think of f being a fish and g being a guppy (minnow). You feed the guppy a …

You can put this solution on YOUR website! Doing only one of the examples. (c) , this indicates the product of f and f, evaluated at x=1.

Question 1090409: Let f (x) = 2x-3 and g (x) = 4x, find (fog) (x) Answer by Cromlix (4381) (Show Source):

You can put this solution on YOUR website! i assume your f times g means fg (x). This means do the g (x) function first, and then that answer is put into the function f.

In the final form there, the variable x appears only once; you could find the inverse by the usual process of switching x and y and solving for the new y. Unfortunately, you still end up having to do awkward algebra to find the inverse.

You can put this solution on YOUR website! I think one is a composition where you substitute for . The other is an actual multiplication of two functions. So if and Then and