Click here to see ALL problems on Proportions; Question 1159450: If g:h = 4:3, evaluate 4g + h : 8g + h Answer by josgarithmetic(39582) (Show Source):

Question 2252: In the following figure:A B C D E F G H I Each of the digits 1, 2, 3, 4, 5, 6, 7, 8, and 9 is: a)Represented by a different letter in the figure above.

Question 372483: Question 372260: Suppose that the functions g and h are defined for all real numbers x as follows. g(x)=x-4 h(x)=4x+2 Write the expression for (g-h)(x) and (g*h)(x) and evaluate (g+h)(-2) Below are my answers but I'm not sure if I got it right. Thanks (g-h)(x)= 8 (g*h)(x)=52 (g+h)(-2)= -12 Answer by Fombitz(32388) (Show Source):

**1. (G • H) v (M • G)** This is a statement, not an argument. It's a disjunction (OR statement) of two conjunctions (AND statements). * **G • H:** This means "G is true AND H is true." * **M • G:** This means "M is true AND G is true." * **(G • H) v (M • G):** This means "Either (G and H are true) OR (M and G are true)."

Question 984743: Suppose that the functions g and h are defined for all real numbers x as follows. g(x) = x-4 h(x) = 4x+2

SOLUTION: Given the functions f(x)=2x-4, g(x)= √x, and h(x)=x^2+9, calculate each of the following a)f(g(9)) b)h(g(9)) c)g(h(4)) d)g(f(10)) e)h(g(f(20))) f)f(g ...

The idea is to assume ~H is the case, and show that it leads to a contradiction. This will then mean the opposite of ~H, which is H, must be the true case instead. If ~H is the case, then we can use modus tollens on premise 2 to get ~(D v G) which turns into ~D & ~G after using De Morgan's Law. After using simplification, ~D & ~G turns into ~G.

You can put this solution on YOUR website! find g of h and h of g. Given: g(x)= 4x h(x)= 2x-1. Then g of h: g(h(x)) = 4(2x - 1)

You can put this solution on YOUR website! g(1)= 1+4+2=7 h(1) = -3+2=-1 (g*h)(1) = g(1)*h(1) = 7*(-1)=-7 R^2 Dr. Robert J. Rapalje, Retired

Question 372260: Suppose that the functions g and h are defined for all real numbers x as follows. g(x)=x-4 h(x)=4x+2