2014年5月28日 · By definition delta G is going to be the same as delta Go under standard conditions. dG isn't going to equal zero under standard conditions (because dGo would be zero too), but the equation dGo = -RTlnK assumes the reaction is in equilibrium I think (note we are using K and not Q), which is why dG=O.

2010年8月10日 · delta G and delta Gnot are really one of the same things: For Gnot, you are in standard conditions so atmospheric pressure is 1ATM, temperature is 25C, and most importantly, all solute species are at 1M. If deltaG = RTln(q/keq) then deltaG = RTln(q) - RT(keq) If all solute species are at 1M, then q = [products] / [reactants] = 1.

2009年6月10日 · K > 1 and standard g > 0 K > 1 and standard g < 0 K < 1 and standard g > 0 K < 1 and standard g < 0 The only way to know this problem is to assume that delta G = 0, so you can set standard g = -RTlnK. The solution says that a galvanic cell generates power via a spontaneous reaction, so standard G must be less than 0.

2009年2月24日 · Its the delta G = Standard G +RTlnK equation that i was having issues with. I think i might be mixing up Keq and K. My initial post had that relationship but I've now double checked and realize my two sources use the same relationships, but one does it with reference to K and delta G, and one does it for Keq and delta G.

2009年4月25日 · the equation deltaG=-RTlnK just relates standard deltaG to the equilibrium constant, using R constant and Temp. to get from standard deltaG to just any delta G (meaning delta G at a different set of conditons other than 25C and 1atm and where all concentrations are 1M), you need to use the equation:

2012年3月25日 · Which of the following statements are true? I. The equilibrium constant of a reaction is directly proportional to the temperature at which the reaction is run. II. The equilibrium constant of a reaction is inversely proportional to the temperature at which the reaction is …

2007年7月14日 · MCAT Study Schedules The 3 Month (100 Day) MCAT Study Schedule Guide: 2022 Edition Study Schedule

2006年7月30日 · delta G = delta G-not + RT ln Q. However, simple log rules tell you that: delta G = delta G-not + RT ln Q\ delta G = -RTlnK + RT ln Q delta G = RT (lnQ-lnK) delta G = RTln (Q/K) The equation essentially tells you, if Q were to be different from K, what would the driving force be to push the reaction towards equilibrium.

2020年5月6日 · So, I am confused about this equation: Delta G = -RTlnK I know delta G has to occur under standard conditions, so the reactants and products would need to be 1M. Wouldn't that make K always 1? So Delta G would always have to be 0? Why is that I see elsewhere that K and G are related? I...

2008年8月13日 · So Nerst's equation is E=E0-(.06/n)log(Q) Q is basically the same equation we use to find K in equilibrium How do we know whether the cathode or the...