2017年10月1日 · The chance that one of the two (bgbgbg or gbgbgb) you are interested in is thus $2/20 = 1/10$. Share. Cite

2017年11月22日 · @GBGBGB . Welcome to the HP Forums, this is a great location to get assistance! I read your post and see that you are unable to select the cardstock option to print. I would like to help you resolve this issue. Click here and refer the card types mentioned under paper handling specifications to check if it is supported.

2015年7月19日 · A while ago I asked one-to-one in combinatorics and then using one-to-one I'll repeat my answer here: There are two distinguishable flagpoles, and there are $19$ flags, of which $10$ are identical...

2018年11月5日 · Still getting a hang of the gbGBGb names). Also the more I look in to it the more I see people having the same problems on FreeNAS forum. Where they have 300MB limit of data transfer.

2017年6月14日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2019年5月26日 · The answer is 4/5. The probability of no girls together given arrangement GBGBGB is 3! for the girl choices and 3! for the boy choices. Thus there is $3!\cdot 3!$ for this arrangement. Moreover there is also arrangement BGBGBG which is likewise the same. Another arrangement is GBBGBG or GBGBBG of which then is similarly the same probability.

2016年3月20日 · What is the number of ways seating three gentleman and three ladies in a row such that each gentleman is adjacent to one lady ?

2020年9月17日 · I suppose you all heard the movie ''The Platform''. Not getting into unnecessary details, there are $333$ rooms and more or less, first $100$ rooms get food. Let's suppose that $100$ rooms are eating

2015年7月18日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2024年3月5日 · Row could look like BGBGBG or GBGBGB and then the permutations of who sits where, and again multiplied by two if they sit in the other row. This is unclear to me is it 2 * (3! + 3!) = 24 * 2 = 48 or 3! * 3! * 2 arrangements and then * 2 again for 2 rows.