2019年12月24日 · They are are arranged as GBGBGBGB This means that there are once again (4!)^2 possibilities. Hence, all together there are 2*(4!)^2 possibilities or 1152 possibilities.

Question 677526: There are four boys and four girls at a party. In how many ways can they be seated in a row if they must sit alternating boys and girls?

2019年5月23日 · Look at it this way; if you were instead counting linear arrangements of boys and girls where no two girls are together, and also the ends are not both girls, there would only be two possible patterns: $$ BGBGBGBG\qquad \text{ and }\qquad GBGBGBGB $$ Each of these can be completed in $4!\times 4!$ ways, so there are $2\times 4!\times 4!$ linear arrangements.

2018年8月20日 · 4 Boys & 4 Girls are to be seated in a line find number of ways , so that Boys & Girls are in alternate seats. My approach: If boys are seated in B$1$,B$2$,B$3$,B$4$ positions than at eac...

$\begingroup$ If no two boys can be adjacent, and no two girls can be adjacent, the arrangement have to alternate BGBGBGBG, or GBGBGBGB. There are $4!^2$ ways to create each configuration. $\endgroup$ –

2023年10月18日 · One approach is to say that the five possible allowed patterns are GbGbGbGb, GbGbGbbG, GbGbbGbG, GbbGbGbG, and bGbGbGbG, with each representing $4!\times4!=576$ ways of ordering the individuals, so $5\times 576=2880$ in total.