
How do you solve cos x = x? | Socratic
2018年2月20日 · Use Newton's method to find: x ~~ 0.73908513322 Looking at the graphs of y = x and y = cos x we see that there is exactly one real solution, actually somewhere in (1/2, 1): …
Fundamental Identities - Trigonometry | Socratic
The best videos and questions to learn about Fundamental Identities. Get smarter on Socratic.
What does cosx sinx equal? - Socratic
2016年3月7日 · So we have cos(x)sin(x) If we multiply it by two we have 2cos(x)sin(x) Which we can say it's a sum cos(x)sin(x) + sin(x)cos(x) Which is the double angle formula of the sine …
Proving Identities - Trigonometry | Socratic
The functions sine, cosine and tangent of an angle are sometimes referred to as the primary or basic trigonometric functions. The remaining trigonometric functions secant (sec), cosecant …
What is the derivative of (cosx)^x? | Socratic
2018年5月29日 · We use a technique called logarithmic differentiation to differentiate this kind of function. In short, we let y = (cos (x))^x, Then, ln (y) = ln ( (cos (x))^x) ln (y ...
How do you find the derivative of y=cos (x) from first principle ...
2014年8月22日 · The 2 which will be useful here are: lim_ (x->0) sinx/x = 1, and lim_ (x->0) (cosx-1)/x = 0 Since those identities rely on the variable inside the functions being the same as the …
How do you find the Taylor series of f(x)=cos(x) ? | Socratic
2014年9月12日 · The Taylor series of f (x)=cosx at x=0 is f (x)=sum_ {n=0}^infty (-1)^nx^ {2n}/ { (2n)!}. Let us look at some details. The Taylor series for f (x) at x=a in general ...
How do find the derivative of y = cos^2 (x)? | Socratic
2015年9月15日 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos (x) and y=tan (x)
What is the derivative of cos^3(x)? | Socratic
2014年12月18日 · The derivative of cos^3 (x) is equal to: -3cos^2 (x)*sin (x) You can get this result using the Chain Rule which is a formula for computing the derivative of the composition …
How do you find the integral of cos^n x ? | Socratic
2017年1月16日 · All you need to do is cancel the I_ns and move the -nI_n to the left hand side: n int cos^n x dx=sin x cos^ (n-1)x + (n-1) int cos^ (n-2)x dx . Dividing through by n gives the …