2015年2月3日 · properties of logarithms ln12-ln2=ln6. Ask Question Asked 10 years, 1 month ago. Modified 10 years, 1 ...

2015年9月28日 · d/dx(ln(6x)) = 1/x ln(6x) = ln6 + lnx ln6 is a constant, so its derivative is 0. d/dx(ln(6x)) = d/dx(ln6) + d/dx(lnx) = 0+1/x = 1/x

2016年7月30日 · ln2+ln6-(1/2)ln9=ln4 We can use lnx+lny=lnxy, lnx-lny=ln(x/y) and 1/nlnx=ln(root(n)x) Hence, ln2+ln6-(1/2)ln9 = ln(2xx6)-ln(sqrt9) = ln12-ln3 = ln(12/3)=ln4

log_6 x = lnx/ln6 f(x) = log_6 x = lnx/ln6 = 1/ln6 * lnx, so f'(x) = 1/ln6 d/dx(lnx) = 1/ln6 * (1/x) = 1/(xln6)

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2017年12月16日 · x=3 As ln(x-1)=ln6-lnx, the domain of x is given by x-1>0 i.e. x>1. As we have ln(x-1)=ln6-lnx or ln(x-1)=ln(6/x) or x-1=6/x or x^2-x=6 or x^2-x-6=0 or x^2-3x+2x-6=0 or (x-3)(x+2)=0 i.e. x=3 or x=-2 But as -2 is not domain, Solution is x=3

Using the exponential logarithm rule, #alogb=logb^a#, #ln5/2+ln6/2+ln7/2# can be written as. #ln5^(1/2 ...

2015年2月24日 · You can use the Chain Rule for the first #ln# while the second is a constant so has derivative equal to zero. You get:

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#ln6-1/2ln(x^2+1)# Answer link. Related questions. What is the common logarithm of 10? How do I find the ...