2016年7月13日 · For this particular, we'd have to use logarithmic differentiation, which works as follows: Let y = (lnx)cosx Taking the natural log (ln) of both sides yields lny = ln((lnx)cosx) lny …

2014年8月10日 · In f (x) = ln (cos (x)), we have a function of a function (it's not multiplication, just sayin'), so we need to use the chain rule for derivatives: d/dx (f (g (x ...

2015年10月16日 · -tanx Rule : d/dxlnu (x)=1/u* (du)/dx therefore d/dx ln (cosx)=1/cosx*d/ (dx)cosx =1/cosx*-sinx =-sinx/cosx =-tanx

2016年12月20日 · Given that: eiθ = cosθ + isinθ cos(− θ) = cos(θ) sin(− θ) = −sin(θ) we can deduce that: cos(θ) = eiθ + e−iθ 2 So: cos(ln(x)) = eilnx + e−ilnx 2 ...

2016年11月1日 · How do you find the derivative of y = ln(cos x2)?

2015年8月30日 · Looking at ∫cos(lnx)dx, we realize that if can't integrate straight away. Next thought is, perhaps we could use substitution. We would need cos(lnx) 1 x to integrate by …

2018年5月29日 · We use a technique called logarithmic differentiation to differentiate this kind of function. In short, we let y = (cos (x))^x, Then, ln (y) = ln ( (cos (x))^x) ln (y ...

Let y = (lnx)cosx, so that ln y= cos x ln ln x Now differentiate both sides, 1 y dy dx = − sinxlnlnx + cosx 1 lnx 1 x dy dx = (lnx)cosx(−sinxlnlnx + cosx xlnx)

2018年5月29日 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos (x) and y=tan (x)

2014年8月21日 · You can find the Arc Length of a function by first finding its derivative and plugging into the known formula: L = ∫ b a √1 + (dy dx)2 dx Process: With our function of …