2017年10月1日 · It does not matter what base we use providing the same base is used for all logarithms, here we are using bease e. Let us define A,B.C as follows=: A = ln a iff a = e^A , B …

2015年9月10日 · We use the fact that lna+lnb=lnab Hence we have that lnx+ln(x-2)=3=>ln(x(x-2))=3=> x(x-2)=e^3=> x^2-2x-e^3=0 The last is a trinomial with respect to x that has the …

2018年7月21日 · 12840 views around the world You can reuse this answer ...

2017年5月12日 · x=10 we need to use the laws of logs. Assuming all the logs have the same base we have the following properties : lnA=lnB=>A=B lnA+lnB=lnAB lnA-lnB=ln(A/B) …

2018年6月14日 · Note firstly that #y# can be expressed more simply. #y=(ln(x^2))^(2x+3)# #y=(2lnx)^(2x+3)# Take the variable out of the exponent by taking logarithms:

2015年6月29日 · 1/x y = ln4x We have a choice. We can either use the chain rule in the form: d/dx(ln(u)) = 1/u * (du)/dx OR we can use properties of logarithms to rewrite the function. …