
What is log 50 to 3 decimal places? - Socratic
log 50 ~~ 1.699 Note that 50 = 100/2 So: log 50 = log (100/2) = log 100 - log 2 ~~ 2-0.301 = 1.699 Note that a very good approximation for log 2 which is worth remembering is 0.30103. The …
How do you calculate log50 with a calculator? - Socratic
2016年10月2日 · You will need a scientific calculator. They work in different ways ... Some you key in 50 first, then press the log key. The answer appears on the display immediately (These …
How do you evaluate log 20 + log 50? | Socratic
2015年6月1日 · log(20) + log(50) = log(20 * 50) = log(1000) = log(10^3) = 3
How do you express log_50 23 in common logarithms? - Socratic
2016年10月31日 · log_50(23) = log_10(23)/log_10(50) = ln(23)/ln(50) Use the identity log_c(a) = log_b(a)/log_b(c) The logarithms commonly found on calculators are base 10, log_10 ...
Common Logs - Precalculus - Socratic
How do you express #log_50 23# in common logarithms? How do you express #log_2 5# in terms of common logs?
How do you solve 10 ^( 2x+1 )= 50? | Socratic
2016年3月7日 · log 50 = log 5 + log 10 = log 5 + 1. Logarithms (of any base ) of expressions on both sides are equal
What is log5? How can we find logs of numbers without using a ...
2016年6月8日 · In fact one need to remember log (to the base #10#) for first ten numbers and it makes things lot easier. Note that while #log1=0# , #log10=1# . In fact, you just need to know …
How do you solve 2 log x = log 25 - Socratic
2015年12月29日 · Use the fact that log(x) is a one-one function as a Real-valued function of Real numbers to find: x = 50 Divide both sides by 2 to get: log(x) = (log(25)+2) / 2 = (2 log(5) + 2 …
Find x for x^(log 5)+5^(log x)=50 - Physics Forums
2014年5月28日 · Homework Statement Find ##x## if ##x^{log 5}+5^{log x}=50## Homework Equations The Attempt at a Solution I tried ##x^{log 5}=50-5^{log x}## and vice versa. Then …
How do you approximate log_5 50 given log_5 2=0.4307 and log …
2016年12月21日 · log_5 50 ~= 2.4307 log_5 50 can be written as log_ 5 (2 xx 25), which can be rewritten as log_a(n xxm) = log_a n + log_a m. => log_5 2 + log_5 25 We know the value of …