2016年10月1日 · 7^(log_7 x) = x with restrictions on the value of x By the very definition of logarithm, for any valid ...

2016年8月12日 · log_7(7)=1 If a^m=b in exponential form, we can write it in logarithmic form as log_ab=m. Let log_7(7)=x and writing it in exponential form, we get 7^x=7=7^1 or x=1 Note - In fact for all values of a, we have log_aa=1

2016年7月15日 · If logs to the same base are being added, then the numbers were multiplied. #log_7 3 + log_7 x = log_7 32# #log_7(3xx x) = log_7 32#

2015年11月30日 · log_7(343) = 3 If x=log_7(343) then we are looking for a value of x such that 7^x= 343 7^1=7 7^2=49 7^3=343 rArr x=3 In most cases a question like this would require the use of a calculator. In this case the question was obviously set up for a direct solution.

Log base "a" of "x" is the same quotient of log base"b" of "x" and log base "b" of "a". This allows us to convert a base that is not easily solvable into the division of of logs with common base that is easy to solve.

2016年3月20日 · 2 log _a a = 1 and log (a^m) = m log a.. log_7 49 = log_7 (7^2) = 2 log_7 7 = 2. 4136 views around the world

Condense the logs on the left -- Subtracting logs of the same base can be rewritten as dividing within the log: #log_ab-log_ac=log_a(b/c)# #log_7(x-3)-log_7x=3# #log_7((x-3)/x)=3# Now use the log rule: If #log_ab=n#, then #a^n=b#. #7^3=(x-3)/x# #343=(x-3)/x# Multiply each side by x: #343x=x-3# Subtract x from each side: #342x=-3# #x=-3/342# #x ...

2018年3月6日 · "The result is:" \qquad \qquad \qquad \quad log_{7} 7^3 \ = \ 3. # "We can evaluate this by using the Rules for Logarithms --" "it may go faster than you think ...

2015年12月29日 · From log definition, we have that log_ba=c <=>b^c=a Thus, log_7(12)=x <=> 7^x=12 Now, we can apply log on both sides of the equation. log7^x=log12 Another log rule states that log_ba^n=n*log_ba, so: x*log7=log12 x=log12/log7 (both on base 10 or base e or whatever base you end up finding convenient! It really does not matter!) Using a calculator, as these are not exact expressions, you can find ...

2016年5月10日 · 9/8 Say that this equation equals x, so 7^(log_7 9-log_7 8)=x Now take the log_7 of both sides to get rid of the powers, log_7 9-log_7 8=log_7 x. We know that loga-logb=log(a/b), so log_7 (9/8)=log_7 x Raise both sides by the base of 7 to remove logarithms, and find the answer 9/8=x