
SOLUTION: Help log5 x = 3 - Algebra Homework Help
log5 x = 3 we do not want the log bit, so we need to remove it. We remove anything in maths by doing the opposite. The opposite of log5 is to raise to base 5: log5 x = 3 becomes 5^log5 x = …
SOLUTION: SIMPLIFY log15- log5 - Algebra Homework Help
SOLUTION: SIMPLIFY log15- log5 Algebra -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: SIMPLIFY log15- log5 Log On Algebra: Logarithm Section
SOLUTION: Without using a calculator, evaluate log5(125).
Without using a calculator, evaluate log5(125).. log5(125)=x convert to exponential form The base raised to the logarithm of the number is equal to the number. logarithm of the number=x, …
SOLUTION: Given that log2=0.3010,log3=0.4771 and …
You can put this solution on YOUR website! Given that log2=0.3010,log3=0.4771 and log7=0.8451.evaluate (a)log5 (b)log49 (c)log14
SOLUTION: Log5 (4x+11)=2 - Algebra Homework Help
Algebra -> Exponential-and-logarithmic-functions-> SOLUTION: Log5 (4x+11)=2 Log On Algebra: Exponent and logarithm as functions of power Section Solvers Solvers
SOLUTION: Use the properties of logarithms to expand the …
log5(10x Algebra -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Use the properties of logarithms to expand the following expression as much as possible. Simplify any …
SOLUTION: log5(x+6)+log5(X+2)=1 - Algebra Homework Help
You can put this solution on YOUR website! log5(x+6)+log5(X+2)=1-----log5[(x+6)(x+2)] = 1----x^2+8x+12 = 5^1
SOLUTION: use log5 2~0.4307 and log5 3~0.6826 to approximate …
SOLUTION: use log5 2~0.4307 and log5 3~0.6826 to approximate the expression without a calculator. log5 18 I need some good examples so that I can figure the rest out for myself th …
SOLUTION: Will someone please help me on these two problems. I …
1. Use log5 2~0.4307 and log5 3~0.6826 to approximate the value of log5 12. 2. Express log6 19 in terms of common logarithms. Then approximate its value to four decimal places. I must …
Answered: use the Laws of Logarithma to evaluate the ... - bartleby
Using the power rule, product rule and the change-of-base formula, simplify the expression log5(250). (Note log(10)log(5) ≈ 1.4.)