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Smallest-circle problem - Wikipedia
The smallest-circle problem (also known as minimum covering circle problem, bounding circle problem, least bounding circle problem, smallest enclosing circle problem) is a computational …
最小圆覆盖算法 - 百度百科
该算法是递归的,并且将两个(有限的)点P和R作为参数;它计算P和R联合的最小包围圆,只要R的每个点都是最终最小包围圆的边界点之一。 因此,原始的最小包围圆问题可以通过调用算 …
Minimal circle containing set of points - Mathematics Stack …
For any set of different points $x$, the circular hull (the minimal circle containing all points) of $x$ is equal to the circular hull of a subset of $x$, that subset having exactly $2$ or $3$ points.
The most direct way to solve the enclosing circle problem is to formulate the problem as a second order cone optimization problem. Suppose the center of the enclosing circle is (x,y), and its …
Minimal Enclosing Circle -- from Wolfram MathWorld
The minimal enclosing circle problem, sometimes also known as the bomb problem, is the problem of finding the circle of smallest radius that contains a given set of points in its interior …
Minimum enclosing circle using Welzl’s algorithm
2025年2月17日 · Given an array arr [] [] containing n points in a 2-D plane with integer coordinates. The task is to find the center and the radius of the minimum enclosing circle …
Minimal Circle_最少几何圆覆盖问题mgdc-CSDN博客
2019年2月7日 · 我们先用p 1 和p [i]做圆,再从2到i-1判断是否有点不在这个圆上,如果都在,则说明已经找到覆盖1到i-1的圆。 如果没有都在:假设我们找到第一个不在这个圆上的点为p [j], …
Smallest Enclosing Circle - Princeton University
The Smallest Enclosing Circle problem (also known as Minimal Enclosing Circle problem in the literature) is the problem of finding the smallest circle that completely contains a given set of …
Minimum Enclosing Circle - GeeksforGeeks
2024年1月7日 · Given an array arr [] [] containing N points in a 2-D plane with integer coordinates. The task is to find the centre and the radius of the minimum enclosing circle (MEC). A …
How can I find the minimal circle include some given points?
2010年6月23日 · I have given some points (2D-coordinates) and want to find the smallest circle, that includes all of this points. The algorithm doesn't have to be very efficient (while it would be …