2020年1月20日 · Any calculation of standard molar entropy requires determining the initial reversible heat flow starting at $\pu{0 K}$, at standard pressure: $$ S^\circ(\pu{298.15 K}) = \int_{0}^{\pu{298.15 K}}\frac{\mathrm{đ}q_\mathrm{rev}}{T} $$ The initial part of this integral (starting at $\pu{0 K}$) can't be done experimentally, and thus has to be based ...

2015年4月14日 · Increasing the molar mass of that specific element increases the entropy. I understand the first one, but I can't grasp the second one. Because naturally you would think that $\ce{H2}$ would have a higher entropy than $\ce{Ne}$ because one mole of it is generally lighter.

2023年12月6日 · It is known that graphite (5.7 J/K mol) has a higher standard molar entropy than diamond (2.4 J/K mol) (data from Physical Chemistry by Atkins). I understand that this must be due to the structural differences between the two allotropes, however I have not been able to find any textbooks or scholarly sources addressing them.

2020年7月30日 · Entropy is dependent on the complexity of the molecule. Due to this, I expected entropy to increase as the complexity of the molecule increased. According to p 918 of Atkins' Physical Chemistry (9th ed.), I noticed that the standard molar entropy of n-hexane at is $\pu{204.3 J mol-1 K-1}$, whereas that for n-butane is $\pu{310.23 J mol-1 K-1}$.

2022年7月9日 · The wording of the cited paragraph is confusing, but it does not say that "the standard molar entropy value is the amount of energy that a substance must have to exist at a certain temperature" (as claimed in the question). In fact the author says specifically that this is …

Without referring to a data table arrange the compounds from highest to lowest standard molar entropy, S. Highest Lowest Answer Bank N (9 CH, OH(g) 0,9 Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

2019年4月8日 · The gas constant is equal to Avogadro's constant times Boltzmann's constant, the latter serving as a proportionality constant between the average thermal (kinetic) energy of the particles in an ideal gas and the temperature:

Without referring to a data table, arrange the compounds from highest to lowest standard molar entropy, S. Highest sº Lowest sº Answer Bank Ne(g) F,(6) HF(8) Calculate the standard entropy change for the reaction at 25 °C. Standard molar entropy values can be found in this table.

Question: CO2(g) has a higher standard molar entropy than Ar(g) mainly because of the difference in molar mass and complexity gases have higher entropies than liquids solutions have higher entropies than solid crystals of the difference in complexity only of the difference in molar mass only CO2(g) has a higher standard molar entropy than CO(g) mainly because KCI(S)

Question: Without referring to a data table, arrange the compounds from highest to lowest standard molar entropy, Sº. Highest sº Lowest S° Answer Bank 0,(8) CH,OH(g) N (8) Show transcribed image text