2019年2月4日 · Answers : (3) Hi Shivam, (CH3)3N has sp3 hybridization on nitrogen withpyramidal shape due to p∏-p∏ bonding...whereas in (SiH3)3N Si has vacant d orbitals which provides p∏-d∏ bonding and so nitrogen has sp2 hybridization with trigonal planar shape..!

2020年9月13日 · The IUPAC name of (CH3)3-N is N,N-Dimethylmethanamine. Explanation: N,N-Dimethylmethanamine, also known as Trimethylamine is an organic compound with the method N(CH₃)₃. It is a colorless, hygroscopic, and flammable tertiary amine. It is a gas at room temperature however is normally offered as a 40% answer in water.

2020年9月13日 · The geometry with respect to the central atom of the molecules, N(SiH3)3, N(CH3)3 and P(SiH3)3 are1) Plan… iva3650 iva3650 14.09.2020

Lone pair of electrons on N in N(SiH3)3 are used up in p-pie d-pie back bonding while in N(CH3)3 such back bonding is not possible due to the absence of vacant d-orbital in carbon. Therefore, N(CH3)3 is more basic than N(SiH3)3.

2020年2月12日 · The bond length will be shortest in BF3 compound so option (3) is correct. In a BF3 molecule, a property called as back bonding exists. Due to back bonding, there is increase in bond order and decrease in bond length. Back bonding does not exist in any of the other compounds, so the bond order of the BF3 molecule is highest.

However, N(CH₃)₃ does not have any such back bonding. So, it will have a pyramidal geometry. The Nitrogen atom has a hybridization of sp³. In this sp³ hybridization, 3 of the hybrid orbitals participate in the bond formation and there is 1 lone pair in the 4th orbital is present.

2022年11月28日 · Answer: N(CH3)3 is pyramidal but N(SiH3)3 is planar because in N(SiH3)3 lone-pair on N−atom is transferred to the empty d− orbitals of silicon (pπ−dπ overlapping) and there is no such possibility in case of N(CH3)3 due to absence of empty d-orbitals on C-atom....

(B) The back bonding in P(SiH3)3 isn't significant like in N(SiH3)3 bcz P has its 3p orbital (large and not so efficient) whereas N has its 2p orbital, more efficient bonding. (C) Back bonding in N(SiH3)3 so N is sp2 hybridised, hence planar. N(ch3)3 is pyramidal.

2021年4月23日 · When 2-bromo-2-methylpropane is refluxed with an aqueous solution of sodium hydroxide, the nucleophilic hydroxide ion substitutes the bromine of the tertiary halogenoalkane to form the tertiary alcohol 2-methylpropan-2-ol: 2-bromo-2-methylpropane + sodium hydroxide → 2-methylpropan-2-ol + sodium bromide (CH3)3CBr

2021年3月21日 · No product will formed when (CH3)3 C- CHO reacts with the following reagents due to: Here, the aldol condensation reaction will not occur as for aldol condensation atleast one alpha hydrogen should be there. Alpha hydrogen is hydrogen at carbon adjacent to carbonyl carbon. But in (CH3)3 C- CHO it is not present.