How do you simplify #(n!)/((n-2)!)#? - Socratic
2015年11月18日 · 56825 views around the world You can reuse this answer ...
How do you simplify the factorial expression #((n+2)!)/(n!)
2017年2月8日 · ((n+2)!)/(n!) = (n+2)(n+1) Remember that: n! =n(n-1)(n-2)...1 And so (n+2)! =(n+2)(n+1)(n)(n-1) ... 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \=(n+2)(n+1)n!
How many electrons are in n = 2? What about n = 4, l = 3? What …
2015年11月17日 · Here's what I got. Since the question is a bit ambiguous, I will assume that you're dealing with three distinct sets of quantum numbers. In addition to this, I will also …
How do you test the series Sigma n^2/2^n from n is [0,oo) for ...
2017年3月2日 · the series converges We can apply d'Alembert's ratio test: Suppose that; S=sum_(r=1)^oo a_n \\ \\ , and \\ \\ L=lim_(n rarr oo) |a_(n+1)/a_n| Then if L < 1 then the series …
Which electronic transition in a hydrogen atom will require
2018年4月5日 · Transition (1), from n=1 to n=2 Start by eliminating choices (3) and 4: the closer to the nucleus (positively-charged) an electron (negatively-charged) lies, the lower its potential …
How do you simplify #((n+2)! )/( n!)#? - Socratic
n^2+3n+2 We can rewrite the numerator as: ((n+2) * (n+2-1) * (n+2-2)!)/((n)!) =((n+2) * (n+1) * (n)!)/((n)!) We can cancel (n)! and (n)! out: =((n+2) * (n+1) * 1)/1 ...
What are the molecular orbital configurations for N_2^+, N_2
2015年11月2日 · If we build the MO diagram for "N"_2, it looks like this: First though, notice that the p orbitals are supposed to be degenerate. They weren't drawn that way on this diagram, …
What is the maximum number of electrons allowed in #n = 2#?
2016年3月11日 · THE MAIN QUANTUM NUMBERS OVERALL DEFINE AVAILABLE ORBITAL SUBSHELLS n is the principal quantum number, indicating the quantized energy level, and …
How do you calculate the wavelength of the light emitted by
2016年12月16日 · How do you calculate the wavelength of the light emitted by a hydrogen atom during a transition of its electron from the n = 4 to the n = 1 principal energy level? Recall that …
How do you calculate the frequency and wave length of ... - Socratic
2017年1月9日 · Now, we evaluate the energy for n=5 and again for n=2, then subtract these values: E_2=(-1311)/2^2= 327.75 (kJ)/(mol) E_5=(-1311)/5^2= 52.44 (kJ)/(mol) Subtract and …