In the case of the $\ce{N2 + O2 -> 2NO}$ , $\Delta H$ and $\Delta S$ are both positive, so the reaction is thermodynamically favorable at high temperature (such as in lightning) but not at low temperature. If the temperature drops to room temperature after NO is formed, it is thermodynamically favorable for NO to decompose to nitrogen and oxygen.

2020年6月16日 · $$\ce{N2 + O2 -> 2NO}$$ So I know the second reaction is endothermic as we need to break triple bonds between nitrogen molecules. I am not sure about the first one. Actually, I want to know if there is some way we can decide whether a reaction is endothermic or exothermic just by looking at the equation?

2017年1月10日 · $\ce O$ is a free oxygen atom and $\ce{O2}$ is two oxygen atoms chemically bound to form an oxygen molecule. There is no common analogy for $\ce C$, but $\ce{N2}$ is called nitrogen, $\ce{H2}$ is hydrogen and $\ce{Cl2}$ is chlorine, each having the same name as that of their constituent elements.

2017年5月11日 · Click here 👆 to get an answer to your question ️ Calculate the bond order of N2,O2,O2^+and O2^- aaakings1245 aaakings1245 11.05.2017

2019年7月22日 · I think that it should be F2 because F is smaller than N and O thus having a small bond length. And small bond length means greater energy (my teacher told me). But the answer is N2.

2019年4月22日 · N2+O2=N2O balance this equation - 9473902. idkidc446 idkidc446 23.04.2019 Chemistry ...

2022年10月18日 · Since we want to determine the Stoichiometric Mixture of propane from the oxygen reading, I am using 78.08% as N2 and 20.95% as O2 for the calculation which gives the N2/O2 ratio of 3.73. The stoichiometric mixture for propane is 15.67. If using N2/O2 ratio of 3.76, the oxygen level at stoichiometric mixture will be approximately 19.75%.

2019年4月14日 · Click here 👆 to get an answer to your question ️ N2 + O2 + H2O = HNO3Balance the equation and name the type of reaction. nidhi199 nidhi199 15.04.2019

2017年4月29日 · So $\ce{N2}$ (or $\ce{O2}$) only has a single vibrational mode $(3 × 2 - 5 = 1),$ no permanent dipole, and can only have a weak induced dipole, so it's absorption in the IR is very small. $\ce{CO}$ also has only a single vibrational mode, but there is a permanent dipole moment and therefore the molecule has the ability to absorb in the IR ...

2014年7月18日 · This phenomenon is explained by s-p mixing. All the elements in the second period before oxygen have the difference in energy between the 2s and 2p orbital small enough, so that s-p mixing (combination) can occur lowering the energy of the σ(2s) and σ*(2s) and increasing the energy of the σ(2p) and σ*(2p) molecular orbitals.