使用本计算器来平衡NH3 + F2 = NH4F + N2化学方程式或反应！

NH3 + F2 = N2F4 + HF is a Double Displacement (Metathesis) reaction where two moles of Ammonia [NH 3] and five moles of Difluorine [F 2] react to form one mole of Tetrafluorohydrazine [N 2 F 4] and six moles of Hydrogen Fluoride [HF]

1 NH 3 + 1 F 2 = 1 NH 4 F + 1 NF 3 For each element, we check if the number of atoms is balanced on both sides of the equation. H is not balanced: 3 atoms in reagents and 4 atoms in products. In order to balance H on both sides we: Multiply coefficient for NH 3 by 4 Multiply coefficient for NH 4 F by 3 4 NH 3 + 1 F 2 = 3 NH 4 F + 1 NF 3

In this video we'll balance the equation NH3 + F2 = HF + NF3 and provide the correct coefficients for each compound.To balance NH3 + F2 = HF + NF3 you'll nee...

2010年8月6日 · 氟气氧化性太强了，反应为nh3+3f2=nf3+3hf，氮元素升高到+3价（nf3）

F2 + NH3 = N2F4 + HF is a Double Displacement (Metathesis) reaction where five moles of Difluorine [F 2] and two moles of Ammonia [NH 3] react to form one mole of Tetrafluorohydrazine [N 2 F 4] and six moles of Hydrogen Fluoride [HF]

Construct the equilibrium constant, K, expression for: NH_3 + F_2 N_2 + HF Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression.

三氟化氮(nf3)是一种无色无味的气体，可由氟与氨反应制得。(1)该反应的方程式为nh3＋f2→nf3＋nh4f，配平方程式并标明电子转移的方向和数目。(2)27.0 ml nf3和水充分反应，生成 18.0 ml no(同温、同压下)，写出反应的化学方程式：_____。

NH3 + F2 = NH4F + NF3 is a Double Displacement (Metathesis) reaction where four moles of Ammonia [NH 3] and three moles of Difluorine [F 2] react to form three moles of Ammonium Fluoride [NH 4 F] and one mole of Nitrogen Trifluoride [NF 3]

1 NH 3 (g) + 1 F 2 (g) = 1 N 2 F 4 (g) + 1 HF(g) For each element, we check if the number of atoms is balanced on both sides of the equation. N is not balanced: 1 atom in reagents and 2 atoms in products.