2017年5月22日 · This means that any complete problem for a class (e.g. PSPACE) which contains NP is also NP-hard. In order to get a problem which is NP-hard but not NP-complete, …

The current hot topic has been the use of PCP Theorem to prove various NP-Hardness results for approximation versions of NP-Hard problems. So, non-determinism is still part of the definition …

A problem in P is in NP by definition, but the converse may not be the case; probably the most important open question in computer science is whether classes P and NP are the same, that …

2019年9月2日 · A problem is said to be NP-hard if everything in NP can be transformed in polynomial time into it, and a problem is NP-complete if it is both in NP and NP-hard. The NP …

Such a problem is NP-hard and in NP. How do we know if a problem is hardest in NP, and no harder problem exists. I understand that let's assume that somehow magically we know that a …

2016年6月15日 · NP-hard if all problems in NP polynomially reduce to it; and NP-complete if all problems in NP polynomially transform to it. What is the difference between polynomial …

NP is the set of all problems that can be checked for correctness if you guess an answer. NP-hard is the set of all problems that are at least as hard as the hardest NP problems. NP-complete is …

2011年5月17日 · I don't know if you would consider it "real life", but exact inference in Bayesian networks is NP-Hard; it's a straightforward reduction from 3-SAT (I guess one could argue that …

2019年11月12日 · $\begingroup$ It might be good to add that while the decision variant of MILP lies in NP, the proof of this is not easy (at the least, proving MILP is NP-hard is a lot easier). …

2015年7月8日 · The problem 3-COLOURABILITY is NP-hard because there is a polynomial time reduction from 3-SAT to 3-COLOURABILITY and there is a reduction from SAT to 3-SAT. It is …