2019年5月15日 · The solubility of $\ce{PbSO4(s)}$ increase with the addition of $\ce{H2SO4}.$ Why? I don't quite understand this. When dissolving $\ce{PbSO4(s)}$ we get the equilibrium equation: $$\ce{PbSO4(s) <=> Pb^2+ + SO4^2-}$$ I know $\ce{H2SO4}$ is a strong acid, that will dissociate completely (or almost completely), like this:

2024年6月2日 · The oxidation number of Pb in PbSO4 is +2. This is because the oxidation number of oxygen is typically -2, and the overall charge of the sulfate ion (SO4) is -2, so the oxidation number of Pb must ...

2024年5月22日 · Yes, PbSO4 (lead(II) sulfate) is an ionic compound. It is composed of lead cations (Pb^2+) and sulfate anions (SO4^2-), which are held together by ionic bonds. Trending Questions

The $\ce{PbSO4}$ formed at the anode is in solid state. Hence, writing it as $\ce{Pb^2+(s)}$ is incorrect, as it is not dissociated into the ions $\ce{Pb^2+}$ and $\ce{SO4^2-}$ . With all these corrections, your final, correct cell representation should be:

2024年6月13日 · The molecular weight of PbSO4 is 303.3 grams per mole. A sample weight of 158.1 grams corresponds to .5213 moles of PbSO4. What is the chemical formula of lead sulphate?

2024年6月22日 · Lead has two oxidation states (+4 and +2). As a result, there are two compounds composed of lead and sulfate: lead(IV) sulfate, which is Pb(SO4)2, and lead(II) sulfate, which is PbSO4.

H2SO4(aq) + Pb(C2H3O2)2(aq) --> PBSO4(s) + 2 HC2H3O2(aq) Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 16.5 g of sulfuric acid and 17.2 g of lead (II) acetate are mixed, calculate the number of grams of sulfuric acid, lead (11) acetate, lead (II) sulfate, and acetic acid ...

2024年6月16日 · The chemical formula for lead sulfate is PbSO4. It is a compound made up of one lead (Pb) ion and one sulfate (SO4) ion. Lead sulfate is a white solid that is sparingly soluble in water.

Solution for 4) Pb + FeSO4 → PBSO4 + Fe 5) CaCO3 → Ca0 + CO2 6) P4+ 3 02 → 2 P203

2018年1月17日 · $\ce{PbSO4 (s) + 2e^- -> Pb (s) + SO4^{2-} (aq)}$ And in this case the $\ce{Pb^{2+}}$ is in solid form and the potential is -0.356 V. In a battery the sulphate is insoluble and it is required that it sticks to the electrode, otherwise the reverse reaction can not occur. A table of potentials can be found here