
How do you simplify the expression #cosx(secx-cosx)#? - Socratic
2016年10月6日 · How do you simplify the expression cos x(sec x − cos x)?
What does sec x equal in terms of sin, cos, and/or tan?
2015年9月15日 · sec alpha=1/cos alpha This comes straight from the definition. Secans is defined as inverse of cosine.
How do you simplify #sec(x) cos(x) - Socratic
2015年7月22日 · secx = 1 cosx Thus, secxcosx = 1 If cosx = A H, then secx = H A
How do you simplify 1/secx? | Socratic
2017年1月26日 · Use the identity: secx = 1 cosx 1 secx = 1 1 cosx = 1 ⋅ cosx 1 = cosx
How do you simplify #(sec x - cos x) / tan x#? - Socratic
2015年8月22日 · Let's start by breaking down some terms. In my opinion, you have to kind of play around with trig stuff to get it to break down right. secx = 1 cosx = tanx sinx So, secx −cosx tanx = secx tanx − cosx tanx = tanx sinx tanx − cosx tanx = 1 sinx − cosx tanx Tangent = sine/cosine, so the reciprocal of the tangent = cosine/sine = 1 sinx − cos2x sinx = …
What is cosx times secx? - Socratic
2016年1月31日 · 1 Your question is: cosx xx secx The trick to this problem is knowing the trigonometric identity: secx=1/cosx Thus, your problem can be written as cosx xx 1/cosx=cosx/cosx=1 The other inverse trigonometric functions are: cscx=1/sinx cotx=1/tanx
How do you simply sec(-x)? - Socratic
2018年2月18日 · Sec and Cos are even functions, meaning they have y-axis symmetry Tan, Cot, Sin, Csc are odd functions, meaning that they have origin symmetry and f (-x) in this case is equal to -f (x).
How do you simplify #tan x/ (sec x - cos x)#? - Socratic
2018年6月2日 · tanx secx −cosx =? tanx = sinx cosx; secx = 1 cosx tanx secx −cosx = sinx cosx 1 cosx −cosx Multiplying numerator and denominator by cosx = sinx 1 − cos2x 1 ...
Fundamental Identities - Trigonometry | Socratic
The best videos and questions to learn about Fundamental Identities. Get smarter on Socratic.
Derivatives of y=sec(x), y=cot(x), y= csc(x) - Calculus - Socratic
The derivatives of \sec (x), \cot (x), and \csc (x) can be calculated by using the quotient rule of differentiation together with the identities \sec (x)=\frac {1 ...