At Sup-C, we have been harnessing our expertise in radiology software development for more than two decades, providing tailored solutions for medical professionals and institutions. From seamlessly connecting DICOM-compatible devices to crafting bespoke software for radiology and pharmaceutical applications, our focus lies in developing ...

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2019年3月7日 · You have shown that $c + \sup A$ is an upper bound to $c + A$, and hence $\sup(c + A) \le c + \sup A$.

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DCMrouter – Sup-C has developed the intelligent DICOM router. This software automates the distribution of DICOM studies to Dicom C-Store compatible devices. DCMrouter automatically simultaneously re-route study data to multiple DICOM nodes with the confidence that data will be accurate when it arrives.

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先后开发了涵盖分子生物学、细胞生物学、免疫学、生物医学等领域的多种试剂及试剂盒。 同时,索莱宝公司提供各种常规生化试剂,库存常备产品多达10000多种,可随时为广大科研工作者提供各类专业试剂。 在质量方面,索莱宝谨记公司信念:质量高于一切。 所有研发的产品都设有严谨的生产流程,科学的质量检测方法和成熟的质量检测程序,我们恪守对每一位用户的承诺:用专业的态度做专业的品牌。 同时,公司组建了一支专业的技术服务队伍,能够为科研工作者提供专业的技术服务 …

2016年10月19日 · Let $A$ and $B$ be sets of real numbers and write $$C=\{x+y:x\in A,y\in B\}.$$ Find a relation among $\sup A$, $\sup B$, and $\sup C$. My attempt: I'm assuming the answer is $\sup C=\sup A+\sup B$.

Let $cx \in cA$ where $x \in A$. Then, $x \le \sup(A)$ by the first property of $\sup$. Therefore, $c \sup(A)$ is an upper bound of $cA$. Let $b$ be another upper bound of $cA$. If $c \ne 0$, then $b/c$ is an upper bound of $A$, so we have $\sup(A) \le b/c$ by the second property of $\sup$, whence $c \sup(A) \le b$.