2016年6月13日 · How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle

2018年3月30日 · Hence, #sec(0) = 1#. Answer link. Related questions. How do you find the trigonometric functions of any ...

2015年9月19日 · You should get sec(0)=1 Secant is a way to write 1/cos; but cos(0)=1 and so: sec(0)=1/cos(0)=1/1=1

2015年10月17日 · cot0: undefined csc0: undefined sec0=1 0 is a special angle. cot, csc, and sec are actually just the reciprocals of tan, sin, and cos respectively.

2016年7月25日 · I changed it to cos: I know that sec(0)=1/cos(0) and that cos(0)=1 so: sec(0)=1

2018年4月5日 · If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot …

If #sec x > 0# and #cot x < 0# in which quadrant does the terminal side of position angle x lie?

2018年3月7日 · If #tan(x) * sec(x)=0# then #color(white)("XXX") {: (tan(x)=0," or ",sec(x)=0), (rarr x" is a multiple of "pi,,"not true for any real value of "x) :}#

2018年4月27日 · cot0 is indeterminate(not defined) tan0 = 0 Also, cot theta = 1/tan theta That would give us cot0 = 1/0 which is an indeterminate form. We can also see that the graph of the …

2017年1月7日 · Given #sectheta>0# and #cottheta<0#, which quadrant does #theta# lie? Trigonometry Right Triangles Relating Trigonometric Functions. 1 Answer