2017年7月19日 · ! [) The above structure is a nucleotide. It consists of a: phosphate group 5-carbon sugar, and nitrogenous base.

2018年3月28日 · We are not told the size of the combinations to be formed. I'll return to this point later. Permutations and Combinations In a permutation order matters, so the permutation (1 2 3) is not the same as (2 1 3). In a combination order does not matter so the combination (2 3) is the same as (3 2). Combinations with or without repetition The question does not say whether we …

2018年3月9日 · color (green) (sqrt3 / 2) sin ( (2pi) / 3) = sin (pi - ( (2pi)/3) )= sin ( (3pi - 2pi) / 3) = sin (pi)/3 sin ( (pi)/3) = sin 60 = sqrt3 / 2

Remember that the limit definition of the derivative goes like this: f '(x) = lim h→0 f (x + h) − f (x) h. So, for the posted function, we have f '(x) = lim h→0 m(x + h) + b − [mx +b] h By multiplying out the numerator, = lim h→0 mx + mh + b − mx −b h By cancelling out mx 's and b 's, = lim h→0 mh h By cancellng out h 's, = lim h→0 m = m Hence, f '(x) = m. The answer above ...

2017年3月21日 · How do you find the volume of the solid whose base is the region bounded by y = x^2, y =x, x = 2 and x = 3, where cross-sections perpendicular to the x-axis are squares?

2016年11月22日 · Adenine, Ribose, and three Phosphate groups. ATP molecules are used by all living organism as energy to carry out life functions. Also notable, ATP stands for Adenosine Triphosphate. This molecule is composed of three parts: Adenine Ribose Three Phosphate Groups Here is a picture: ! [students.ga.desire2learn.com] ()

2018年7月21日 · Place circular base on x-y plane, centred at Origin. At z = 0; x2 +y2 = 16r2 Considering that part of the solid in the 1st octant, with the square cross-sections running parallel to the x-z axis, the volume of a elemental cross section is: dV = x ⋅ 2x dy = 2(16r2 − y2)dy Thus: V = 2∫ 4r 0 dy (16r2 − y2) = 2[16r2y − y3 3]4r 0 = 256 3 r3 Volume in 1st Octant is only 1 4 of the …

2015年10月23日 · See the explanation section, below. Rewrite the integrand using tan^2x = sec^2x-1. Let's give the integral we want the name I I = int tan^2xsec^3x dx = int (sec^5x-sec^3x)dx Next we'll integrate sec^5x by parts. int sec^5x dx = int sec^3 x sec^2x dx Let u = sec^3 x and dv = sec^2x dx.

The formulas for circumference, area, and volume of circles and spheres can be explained using integration. By adding up the circumferences, 2\\pi r of circles with radius 0 to r, integration yields the area, \\pi r^2. The volume of a sphere can be found similarly by finding the integral of y=\\sqrt{r^2-x^2} rotated about the x-axis.

2015年3月22日 · For 1< x< 4, let b (x)=-x^2+5x-4. This will be the base of the equilateral triangle cross-section at x. The solid itself looks something like this: Now draw the cross-section equilateral triangle, label the sides b (x), and draw a vertical line for the height h (x) from the top vertex down perpendicular to the base.