2020年11月19日 · sin 130° = 0.76604. Explanation: The sin of 130 degrees is 0.76604, the same as sin of 130 degrees in radians. To obtain 130 degrees in radian multiply 130° by π / 180° = 13/18π. Sin 130degrees = sin (13/18 ×π). please give thanks to my answer. please mark my answer as the brainliest. please follow me

Question 808804: Find all solutions for a triangle with C=130 degrees, c=17, and b=5. Round to nearest tenth. Round to nearest tenth. Answer by stanbon(75887) ( Show Source ):

sin(B)/b = sin(C)/c sin(130)/104.41800354 = sin(y)/50 I'll let the student handle the scratch work to solve for angle y. You should arrive at the previously mentioned y value. Or very close to it. This is the approximate measure of angle ACB. Adjacent to this is angle ACD, which has measure of 52-y = 52-21.51940163 = 30.48059837 degrees ...

what is the value of the following function? cos(130°)cos(10°) + sin(10°) sin(130°)... Addition formula for cosine: cos(s-t)=cos s cos t+sin s sin t For given equation: cos(130°)cos(10°) + sin(130°) sin(10°)=cos(130º-10º)=cos 120º In standard position 120º terminates in quadrant II where cos is negative. reference angle=180-120 =60º

If sin(x)=-5/13 and x is in quadrant III,... So for angle x, we have a 5-12-13 right triangle in quadrant III, where x =-12, y=-5, and r=+13. There is often a conflict of notation when x is used for an angle, and also for values of the adjacent side of the defining right triangle.

Use the formula sin(A+B) =sin(A)cos(B)+cos(A)sin(B) by substituting A=132°, B=138°, then use sin(270°) = -1 2) Simplify cos [a+pi/3] Use cos(A+B) = cos(A)cos(B)-sin(A)sin(B) with A=a and B= then use and 3) Find the exact value of sin (60*+45*) Use sin(A+B) =sin(A)cos(B)+cos(A)sin(B) with A=60° and B=45° and and

2018年8月29日 · Hey buddy you answer is here.... _____ _____ ...

Question 852468: Write the expression as the cosine of the angle cos130(degrees)cos40(degrees) + sin130(degrees)sin40(degrees)

2024年6月23日 · If x = sin 130° + cos 130° then - 60656012. shaistafaru shaistafaru 23.06.2024 CBSE BOARD XII ...

We also know that Area(ADE) = (1/2) * DE * AE * sin(A) and since triangles are similar, the angles are the same. Since we have two unknowns (AC and C), we need another equation. We know that the ratio of the sides is 150/400 = 3/8.