
How do I find the value of sin 5pi / 6? - Socratic
2015年8月8日 · sin (5pi)/6= 1/2 Sin (5pi)/6= sin (pi- pi/6)= sin pi/6= sin 30 = 1/2 Another way to think about it is to draw the angle in a Unit circle and create the "new" triangle in Quadrant II. Drop a perpendicular to the x-axis and you will have the correct triangle to use. From this triangle, you need the opposite leg length, which is 1/2. Since the …
How do you evaluate Sin 5pi? - Socratic
2015年5月8日 · sin 5pi = sin (pi + 4pi) = sin pi = 0. How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?
How do you find the exact value of sin (5pi)/3? - Socratic
2015年9月25日 · How do you find the exact value of #sin (5pi)/3#? Trigonometry Right Triangles Trigonometric Functions of Any Angle. 1 Answer
How do you find #sin^-1(sin ((5pi)/6))#? - Socratic
2018年3月27日 · sin^-1(sin(5pi)/6)=pi/6 sin((5pi)/6)=1/2, so we're really being asked for sin^-1(1/2). Let y=sin^-1(1/2) Then, from the definition of arcsine, 1/2=sin(y) ( y=sin^-1(a) hArr a=sin(y) ) In other words, we want to know where the sine function returns 1/2. Sine is equal to 1/2 for pi/6+2npi, (5pi)/6+2npi, where n is any integer. But really, since the domain of arcsine is [-pi/2, pi/2], pi/6 is the ...
What are the six trig function values of 5pi? | Socratic
2015年12月31日 · sin(5pi) = 0 cos(5pi) = -1 tan(5pi) = 0 sec(5pi) = -1 csc(5pi) is "undefined" cot(5pi) is "undefined" First, let's note that sine and cosine are periodic with period 2pi, meaning for any integer k, sin(x) = sin(x+k2pi) and cos(x) = cos(x+k2pi) With this, we get the first two desired values: sin(5pi) = sin(pi + 2(2pi)) = sin(pi) = 0 and cos(5pi) = cos(pi+2(2pi)) = cos(pi) = -1 The remaining ...
How do you find the value of #sin((5pi)/12)#? - Socratic
2016年7月23日 · You use the formula for the sine of a sum: sin(a+b)=sin a cos b+cos a sin b Think of a pie divided into twelve slices. Three of them form one quarter, two more form one sixth of the pie. So, thinking of the "pie" as \pi: {5 pi}/{12}={pi}/4+{pi}/6.
How do you evaluate sin 5pi/3? - Socratic
2018年5月27日 · Use trig table. #sin ((5pi)/3)) = sin (-pi/3 + (6pi)/3) = sin (- pi/3 + 2pi) = sin (-pi/3) = - sin (pi/3) = - sqrt3/2#
What are the six trig function values of (5pi)/3? | Socratic
2018年5月17日 · Use trig table and unit circle --> #sin ((5pi)/3) = sin (-pi/3 + (6pi)/3) = sin (-pi/3) = - sin pi/3 = - sqrt3/2#
How do I find the value of sin (5Pi/4)? - Socratic
2015年9月24日 · Find sin ((5pi)/4) Ans: -sqrt2/2 Trig unit circle shows --> sin ((5pi)/4) = - sin (pi/4) Trig Table of Special Arcs gives --> sin (pi/4) = sqrt2/2, therefor: sin ...
What are the six trig function values of (5pi)/6? - Socratic
2015年12月16日 · (5pi)/6 has a reference angle of pi/6, so all its trig values will be related to the values for pi/6. Also notice that (5pi)/6 is located in the second quadrant, so... "SINE" will be positive.