
How do you find the 6 trigonometric functions for 60 degrees?
2015年8月27日 · sin(60^@) = sqrt(3)/2color(white)("XX")csc(60^@) = 2/sqrt(3) cos(60^@) = 1/2color(white)("XXXX")sec(60^@) = 2 tan(60^@) = sqrt(3)color(white)("XXX")cot(60^@)=1/sqrt(3) Use the basic trigonometric definitions and the diagram below. Note: only the left half triangle is directly relevant; both sides combine to form …
How do you find the exact value of - Socratic
2015年4月26日 · 30^o " and " 60^o "are angles of one of the standard triangles" sin(30^o) = 1/2 cos(30^o) = sqrt(3)/2 sin(60^o) = sqrt(3)/2 cos(60^o) = 1/2 So sin(60^o)*cos(30^o) + sin(30^o)*cos(60^o) =(sqrt3/2)(sqrt3/2) +(1/2)(1/2) = 3/4 +1/4 =1
Calculate x? Sin(x+60)=2Sinx - Socratic
2018年5月27日 · First, we apply compound angle formula on #sin(x+60)#. #sin(x+60) = sin(x)cos(60) + sin(60)cos(x) = 1/2sin(x) + sqrt(3)/2cos(x)# We now have: #2sin(x) = 1/2sin(x) + sqrt(3)/2cos(x)# Since #sin(x)# is not equal to 0 (if #sin(x)# is equal to 0, it is not possible for #sin(x+60)# to be equal to 0 as well), we can divide both sides of the equation ...
How do you find the six trigonometric functions of 300 degrees?
2015年5月25日 · Use the trig unit circle as proof. sin 300 = sin (-60 + 360) = sin (-60) = -sin 60 = (-sqrt3)/2 cos 300 = cos (-60 + 300) = cos 60 = 1/2 tan 300 = (-sqrt3)/2 : (1/2 ...
How do you solve #sin(105^@)=sin(60^@+45^@)#? - Socratic
2017年12月7日 · Use the identity sin(A+B) = sin(A)cos(B)+cos(A)sin(B). The values for the sine and cosine of 60^@ and 45^@ are well known; use them to simplify the result. Given: sin(105^@)=sin(60^@+45^@) Use the identity sin(A+B) = sin(A)cos(B)+cos(A)sin(B) where A=60^@ and B=45^@: sin(105^@)=sin(60^@)cos(45^@)+cos(60^@)sin(45^@) The sine and …
What is sin 120 degrees? - Socratic
2015年5月30日 · On the trig unit circle: sin 120 = sin (180 - 60) = sin 60 = sqrt3/2
How do you find the value of sin 240? - Socratic
2015年10月17日 · Trig unit circle --> sin (240) = sin (60 + 180) = - sin 60. Trig Table of Special Arcs --> #- sin 60 = - sqrt3/2#
How do you solve sin(60-x)=2sinx? - Socratic
2015年5月3日 · Use the trig identity: sin (a - b) = sin a.cos b - sin b.cos a sin (60 - x) = sin 60.cos x - cos 60.sin x = (sqr3/2).cos x - (sin x)/2 (sqr3).cos x - sin x = 4.sin x f(x) = (sqr3).cos x - 5sin x = 0. Divide by cos x --> (Condition: cos x not 0 -> x not pi/2 and x not 3pi/2) f(x) = sqr3 - 5tan x -> tan x = (sqr3)/5 = 0.35 Calculator gives x = 19.10 + k.pi#
How do I find the value of sin 300? - Socratic
2015年9月11日 · We have that #sin300=sin(360-60)=sin360*cos60-cos360*sin60=0-sin60=-sqrt3/2# Answer link. Related questions.
How do you find the value of csc 60? - Socratic
2015年6月8日 · csc 60 = 1/sin 60 Trig conversion table gives-> sin 60 = (sqrt3)/2 csc 60 = 2/(sqrt3) = (2sqrt3)/3