Use the Sum to Product identity: sin (s) − sin (t) = 2 sin (2 s − t ) cos (2 s + t ) = 2 sin (2 9 x − x ) cos (2 9 x + x ) Simplify 2 sin ( 2 9 x − x ) cos ( 2 9 x + x ) : 2 sin ( 4 x ) cos ( 5 x )

Use \displaystyle \sin x=\cos\left(\frac\pi2-x\right) and \displaystyle\cos2y=1-2\sin^2y

Use the form asin(bx−c)+ d a sin (b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. Find the amplitude |a| | a |. Find the period of sin(9x) sin (9 x). Tap for more steps... Find the phase shift using the formula c b c b. Tap for more steps... List the properties of the trigonometric function.

Use the form asin(bx−c)+ d a sin (b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. Find the amplitude |a| | a |. Find the period of sin(9x) sin (9 x). Tap for more steps... Find the phase shift using the formula c b c b. Tap for more steps... List the properties of the trigonometric function.

sin x tan x – 1 = tan x – sin x If secx cos5x + 1 = 0, where \[0 < x \leq \frac{\pi}{2}\], find the value of x. Write the number of solutions of the equation tan x + sec x = 2 cos x in the interval [0, 2π].

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prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx

华理士公式，可以求任意x \in [0, \frac{\pi}{2}]的n次cos和sin的积分. 推导可以用定积分的分部积分法

2021年6月7日 · sin 9x = sin x. ⇒ sin 9x - sin x = 0. Using transformation formula: sin A - sin B = 2 cos \(\frac{A+B}2\) sin \(\frac{A-B}2\) ∴ 2 cos \(\frac{9x+x}2\) sin \(\frac{9x-x}2\) = 0. ⇒ cos 5x sin 4x = 0. ∴ cos 5x = 0 or sin 4x = 0 . If either of the equation is satisfied, the result will be 0