2015年4月16日 · cos x With pi/2 add to any angle measure, sin changes to cos and vice- versa. Hence It would change to cosine and since the angle measure falls in the second quadrant, hence sin (x+pi/2) would be positive.

2016年8月16日 · cost Using the appropriate color (blue)"addition formula" color (red) (|bar (ul (color (white) (a/a)color (black) (sin (A+B)=sinAcosB+cosAsinB)color (white) (a/a ...

2015年4月23日 · for the "true" proof you need to use matrice, but this is acceptable : sin(a + b) = sin(a)cos(b) +cos(a)sin(b) sin(π 2 + x) = sin(π 2) ⋅ cos(x) + cos(π 2) ⋅ sin(x) sin(π 2) = 1 cos(π 2) = 0 So we have : sin(π 2 + x) = cos(x) Since this answer is very usefull for student here the full demonstration to obtain sin(a + b) = sin(a)cos(b) +cos(a)sin(b) (do not read this if you are not …

2017年2月2日 · sin (a-pi/2)=-m We can use two formulas here. One sin (-A)=-sinA and sin (pi/2-A)=cosA Hence sin (a-pi/2)=sin (- (pi/2-a)) = -sin (pi/2-a)=-cosa=-m

2015年5月15日 · Construct a right angled triangle with angles x, (π 2 − x) and π 2, with hypotenuse of length 1. It is possible to do this since these angles add up to π. Then the side opposite the angle x will have length sinx and the side opposite the angle (π 2 …

2015年9月15日 · If P (x,y) submits alpha at the centre of unit circle, x = cos alpha , y = sinalpha, tanalpha = y/x. etc. For alpha = pi/2 , x = 0, y = 1. => cospi/2 = 0, sinpi/2 = 1 and tanpi/2= 1/0 (undefined) cscpi/2 = 1,secpi/2 = 1/0 (undefined) and cotpi/2 = 0.

2015年5月19日 · The range of arcsin is -pi/2 <= theta <= pi/2. 2 > pi/2 so it lies outside the range. Use sin (pi-theta) = sin theta Then sin2 = sin (pi-2). pi-2 ~= 1.14 so 0 < pi-2 < pi/2 So arcsin (sin (2)) = pi-2

2016年1月20日 · If you want to know how please follow. sin(− π 2) = −sin(π 2) since sin(x) is a odd function. sin(− π 2) = −1 since sin(π 2) = 1 arcsin(sin(− π 2)) = arcsin(−1) Now comes the range of arcsin(x) The range of arcsin(x) is [− π 2, π 2] So arcsin(−1) would give − π 2 Therefore, arcsin(sin(− π 2)) = − π 2

2016年3月12日 · The statement is true when the inverse trig functions refer to the principal values, but that requires more careful attention to show than the other answer provides. When the inverse trig functions are considered multivalued, we get a more nuanced result, for example x = sin(3π 4) = cos(π 4) = 1 √2 but 3π 4 + π 4 = π. We have to subtract to get π 2.

2016年5月1日 · This is a well used trig. relation along with sin(π 2 −θ) that is : cos(π 2 − θ) = sinθ and sin(π 2 −θ) = cosθ Basically sin (angle) = cos (complement) and cos (angle) = sin (complement) example: sin60∘ = cos30∘etc However, we can show the above question using the appropriate Addition formula