2018年1月11日 · sin(pi/6) = 1/2 Start with an equilateral triangle of side 2. The interior angle at each vertex must be pi/3 since 6 such angles make up a complete 2pi circle. Then bisect the triangle through a vertex and the middle of the opposite side, dividing it into two right angled triangles. These will have sides of length 2, 1 and sqrt(2^2-1^2) = sqrt(3). The interior angles of each right angled ...

2018年4月27日 · In this case, #pi/6# refers to the angle in radians, an alternate unit of measurement for angles (#pi# rad = 180°). The point on the unit circle that is intersected by this line is (#sqrt(3)/2#, #1/2#). Finally, the function, sin(#theta#) returns a value equal to the y-coordinate of the point, giving us an answer of #1/2#.

2018年4月13日 · How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle

2016年5月13日 · 1/2 Consider a right triangle ABC with angle A = pi/6 = 30^@, Angle B = 60^@, angle C = 90^@. Call hypotenuse AB = a --> side BC = a/2 sin (pi/6) = (a/2)/a = 1/2

2016年5月26日 · It is sin(pi+pi/6)=-sin(pi/6)=-1/2. How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle?

In our case we have: #theta=pi/6=3.14/6=0.523# and: #sin(pi/6)=sin(0.523)=0.523-0.024+3.26*10^(-4)-...=0.499approx0.5# You can find the Taylor series for the other trigonometric functions such as: (Picture source: www.efunda.com)

2018年7月15日 · (sqrt3+1)/2 For problems like these, it helps to memorize the Unit Circle. On the Unit Circle, the coordinates for pi/6 (30^@) are (sqrt3/2,1/2) Where the x-coordinate is the cosine value and the y-coordinate is the sine value.

2016年4月27日 · How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle

2015年8月8日 · sin (5pi)/6= 1/2 Sin (5pi)/6= sin (pi- pi/6)= sin pi/6= sin 30 = 1/2 Another way to think about it is to draw the angle in a Unit circle and create the "new" triangle in Quadrant II. Drop a perpendicular to the x-axis and you will have the correct triangle to use. From this triangle, you need the opposite leg length, which is 1/2. Since the …

2016年8月26日 · Here, it is sin^(-1)sin(pi/6)=pi/6. It is important to note that sin (pi/6) = sin (13/6pi)=1/2 and, while ...