
Why does #cos(90 - x) = sin(x)# and #sin(90 - x) = cos(x)#? - Socratic
2015年4月17日 · Note that the image below is only for x in Q1 (the first quadrant). If you wish you should be able to draw it with x in any quadrant. Definition of sin(x) (side opposite angle …
What is #sin(x-90)#? - Socratic
2015年12月17日 · Use the sine angle subtraction formula: #sin(alpha-beta)=sin(alpha)cos(beta)-cos(alpha)sin(beta)# Therefore, #sin(x-90˚)=sin(x)cos(90˚)-cos(x)sin(90˚)#
What is sin(-90 degrees)? - Socratic
2015年5月13日 · Consider that -90° corresponds to 270° (the minus sign is to turn clockwise instead of counter-clockwise): so: sin(-90°)=sin(270°)=-1 Trigonometry Science
How do you find the 6 trigonometric functions for 90 degrees?
2015年9月21日 · Using a unit circle (so the hypotenuse #=1#) and its intersection with an angular arm in standard position:. the six basic trigonometric functions are defined as
How do you find the exact value of #sin(-90)#? - Socratic
2018年3月7日 · sin (-90) = -1 sin -90 = sin (360 - 90) = sin 270 Angle 270^@ is third quadrant, where only tan and cot are positive.
How do you prove sin(90°-a) = cos(a)? - Socratic
2016年6月30日 · We know the angles in a right triangle, and a triangle in general, must add to 180^o, so if we have an angle of 90 and an angle of a, our other angle must be 90-a: (a)+(90 …
How do you simplify #sin(90 + x)#? - Socratic
2015年8月14日 · sin (90 + x) = cos x sin (90 + x) = cos x Method 1: Using plots of sin x and cos x. ... Is sine, cosine ...
How do you verify the identity sin(90+A)=cosA? - Socratic
2016年12月21日 · Expand using the rule sin(A + B) = sinAcosB + cosAsinB. sin(90 + A) = cosA sin90cosA + cos90sinA = cosA We know, by the unit circle, that sin90˚ = 1 and cos90˚ = 0. …
When two waveforms are out of phase by 90? - Answers
2022年4月28日 · If two waveforms are out of phase by 90 degrees, this is a quarter cycle. If you are looking at a symmetric sine wave that oscillates around zero then one wave will be at its …
How do you graph #y = 2sin(theta+90°)#? - Socratic
2018年5月15日 · See below. First of all, observe that sin(\\theta + pi/2) = cos(\\theta). So, your equation becomes y=2cos(\\theta). From here, assuming you're familiar with the graph of the …