How do you find the square root 28? - Socratic
2015年9月11日 · Unfortunately the only easy way to do this is by using a calculator to get #color(white)("XXX")sqrt(28)=5.291503#
What is the square root of 28 in simplified radical form?
2015年9月18日 · #sqrt(28) = sqrt(14*2) = sqrt(7*2*2) = sqrt(7*2^2) = 2sqrt(7)# Answer link. Related questions
SOLUTION: Simplify square root of 28 - Algebra Homework Help
square root of 28 Found 2 solutions by checkley77, rapaljer: Answer by checkley77(12844) (Show Source ...
How do you simplify square root of 175 minus square root of 28?
2015年7月29日 · sqrt175-sqrt28 = 3sqrt7 First, simplify each square root: sqrt175, is 175 divisible by a perfect square (other than 1)? We could go through the list starting with 2^2 = 4 is not a factor and 3^2 = 9 is not a factor, and when we get to 5^2 = 25, we find that: 175 = 25xx7 So sqrt175 = sqrt(25xx7) = sqrt25xxsqrt7=5sqrt7. We cannot further simplfy sqrt7 so we'll simplify …
What is the square root of 28? - Socratic
2018年4月14日 · What is the square root of 28? ... (28) = sqrt(7(2^2)) = 2sqrt(7)# Answer link. Related questions. How do ...
How do you simplify #7sqrt(28)#? - Socratic
2018年3月5日 · You find perfect squares that are factors in the radical. √28 √4=2 7*2√7 14√7
SOLUTION: simplify: square root of 112 + square root of 28. I don't ...
the factors 16*7. Notice that 16 is a perfect square. And now you can apply the rule:.. Then you can take the square root of 16 to get 4. So you can replace the square root of 16 by 4 and you have . So you have simplified down to.. You can next apply the same sort of simplification to . Notice that 28 can be factored into 4*7 and that 4 is a ...
How do you simplify Square root of 63 - Square root of 28?
2018年3月3日 · \\sqrt{63}-\\sqrt{28}=\\sqrt{3^2*7}-\\sqrt{2^2*7}=3\\sqrt{7}-2\\sqrt{7}=\\sqrt{7}
SOLUTION: How do I simplify the 63 squared - 28 squared?
To simplify a square root, you look for perfect square factors of the radicand (the expression inside the radical). Both of your radicands, 63 and 28, have perfect square factors: 9 and 4 respeoctively. So we can rewrite your expression in this form: Now we can use a property of radicals, , to separate the two factors into separate square roots:
How do you simplify the square root of 28 times the square
2018年3月24日 · 14sqrt(2) You can rewrite each radicand as a product of its prime factors: sqrt(28) * sqrt(14) = sqrt(2*2*7) * sqrt(2*7) You can then separate each factor into individual radicands: sqrt(2*2*7) * sqrt(2*7) = sqrt(2) * sqrt(2) * sqrt(2) * sqrt(7) * sqrt(7) Next multiply the square roots that have a matching pair: sqrt(2) * sqrt(2) * sqrt(2) * sqrt(7) * sqrt(7) = 2 * sqrt(2) …