How do you find the square root of 7? - Socratic
2016年8月31日 · sqrt(7) ~~ 2.645751311 Since 7 is a prime number, it has no square factors and its square root cannot be simplified. It is an irrational number, so cannot be exactly represented by p/q for any integers p, q. We can however find good rational approximations to sqrt(7). First note that: 8^2 = 64 = 63+1 = 7*3^2 + 1 This is in Pell's equation form: p^2 = n q^2 + 1 with n = 7, p …
What is the square root of 7 times the square root of 2?
2015年9月21日 · sqrt14 Simply multiply the radicals to get the answer.
How do you simplify (square root 7) (square root 14)? - Socratic
2015年10月5日 · #sqrt(7)*sqrt(14)# #color(white)("XXX")=sqrt(7)*sqrt(7)*sqrt(2)# #color(white)("XXX")=7sqrt(2)#
What is the square root of 5 times the square root of 7?
2015年9月14日 · sqrt 35 Both 5 and 7 are prime numbers so they cannot be factored. sqrt 5xxsqrt7=sqrt 5sqrt7=sqrt35
Is #sqrt7# a rational, irrational, natural, whole, integer ... - Socratic
2015年7月10日 · sqrt(7) is an irrational number. That is, it cannot be expressed as p/q for some integers p and q with q != 0 How do we know that sqrt(7) is irrational? For a start, 7 is a prime number, so its only positive integer factors are 1 and 7. Next suppose sqrt(7) = p/q for some positive integers p and q. Suppose further that p/q is in lowest terms - that is p and q have no …
What is the complex conjugate of the square root of -7?
2015年9月6日 · I suppose: -sqrt(7)i and +sqrt(7)i In your case you have: sqrt(-7)=sqrt(-1*7)=sqrt(7)i where sqrt(-1)=i is the Imaginary Unit. The complex conjugate f your complex number: z=0+sqrt(7)i will be obteined chaging signs as: z=0+sqrt(7)i=+sqrt(7)i z=0-sqrt(7)i-sqrt(7)i
How do you simplify 1/square root of 7? - Socratic
2018年4月30日 · sqrt7/7 To simplify 1/sqrt7 we must eliminate the radical denominator. To do this, multiply the numerator and denominator by sqrt7 1/sqrt7 * sqrt7/sqrt7 = sqrt7/7
How do you find the square root of 49? - Socratic
2016年7月22日 · The square root of a number is that number which, when multiplied by itself will equal the original number. #4 xx 4 = 16 rArr 4^2 = 16# This means #sqrt16 = 4# To find the square root of a number, find its prime factors. #49 = 7xx7# #sqrt49 = sqrt (7xx7) = sqrt 7^2 = 7# (A square root can also be a negative number.)
Simplification of Radical Expressions - Algebra - Socratic
There are two common ways to simplify radical expressions, depending on the denominator. Using the identities #\sqrt{a}^2=a# and #(a-b)(a+b)=a^2-b^2#, in fact, you can get rid of the roots at the denominator.
Graphs of Square Root Functions - Algebra - Socratic
Now, let's explore how to translate a square root function vertically. y = #sqrt(x) + 3# or y = #sqrt(x) - 4#. The addition or subtraction on the OUTSIDE of the square root function will cause the graph to translate up or down. Adding 3 will raise the graph up, and subtracting 4 will lower the graph by 4 units. (see graph)