Sep 15, 2015 · tan 2pi=0 You can use the period of the trigonometric function to reduce 2pi to 0, so you have tan 2pi=tan 0 To calculate tan 0 you can use the formula tan alpha= sin alpha/cos alpha. From this formula you get: tan 0=sin 0/cos 0=0/1=0

Dec 4, 2016 · How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#?

How do you verify #cos 2x = (1-tan^2x)/(1+tan^2x)# using the double angle identity? How do you use find the exact value of cos2x, given that cotx = -5/3 with pi/2<x<pi? How do you use a double-angle formula to find the exact value of cos2u when sin u = 7/25, where pi/2 <u < pi?

How do you find the period of #tan(2pi x) #? Trigonometry Graphing Trigonometric Functions Amplitude, Period and Frequency. 1 Answer

Feb 26, 2018 · Here, #tan^2(pi/7)+tan^2((2pi)/7)+tan^2((3pi)/7)# #=tan^2(pi/7)+tan^2((2pi)/7)+tan^2(pi+(4pi)/7)# #=tan^2(pi/7)+tan^2((2pi)/7)+tan^2((4pi)/7)#

Jul 19, 2015 · Note that the angle ((-2pi)/3) occurs in the third quadrant and is a positive value (based on CAST or recognition that both the "rise" and the "run" are negative, so the ratio tan = rise/run is positive).

Apr 24, 2018 · Given that tan #2pi//9=0.8391#, use equivalent trigonometric expressions to evaluate cot #5pi//18#, to four decimal places?

Mar 6, 2018 · Letting #x=pi/7#, we have, #"The R.H.S.="(3-tan^2x)/(1-tan^2x)#, #=(3cos^2x-sin^2x)/(cos^2x-sin^2x)#, #={3*1/2(1+cos2x)-1/2(1-cos2x)}/(cos2x)#,

Dec 21, 2016 · tan (x) tan (x - 2pi) = tan x. How do you use the sum and difference identities to find the exact value of tan 105 degrees?

Apr 23, 2018 · tan(-{2pi} /3 ) = sqrt{3} Pro tip: Almost every question in trig involves a 30,60,90 triangle or a 45,45,90 triangle.