
What is #tan^-1(sqrt3/3)#? - Socratic
2018年3月6日 · Let #theta = tan ^-1 (sqrt3/3)# #tan theta = sqrt3 / 3# #tan theta = cancel sqrt 3 / ( sqrt 3 * cancel sqrt3# #tan theta = 1 / sqrt 3# From the above table, #tan theta = 1 / sqrt 3 # or #theta = =( pi / 6)^c # or #30^@#
How do you find the value of #tan^-1 sqrt(3)#? - Socratic
2015年10月24日 · Note #tan^(-1)# is defined as a function with values restricted to the range #[0,pi/2)# and if #theta = tan^(-1)(sqrt(3))# then #tan(theta) = sqrt(3)# A basic reference triangle looks like: #theta= 60^@ = pi/3#
How do you solve #tan θ = sqrt 3 - Socratic
2016年5月23日 · General solution is npi+pi/3, wheren is an integer tantheta=sqrt3=tan(pi/3) i.e. theta=pi/3 A tangent function has a cycle of pi and repeats after every pi Hence General solution is npi+pi/3, wheren is an integer
How do you solve tanx=sqrt3? - Socratic
2016年9月29日 · Consider a triangle with sides #1#, #sqrt(3)/2# and #2#. This is a right angled triangle and one half of an equilateral triangle... Now #tan theta = "opposite"/"adjacent"# So looking at our diagram, #tan (pi/3) = sqrt(3)/1 = sqrt(3)# So one solution of the given equation is #x = pi/3# Note that:
How do you evaluate #Tan[arccos ( - sqrt ( 3 ) / 2 ) ]#? - Socratic
2015年11月14日 · #tan(theta) = sin(theta)/cos(theta)# #sin(theta) = +-sqrt(1 - cos^2(theta))# During the arccosine range, the sine is always positive so
How do you evaluate #arctan((sqrt (3)) /3)#? - Socratic
2016年4月26日 · arctan(sqrt(3)/3)= pi/6=30^@ Note that sqrt(3)/3 = 1/sqrt(3) Here is a standard trigonometric triangle with this ratio for the tan: Note that by definition the arctan function has a range of [0,pi) Trigonometry
How do you find the exact value of #arctan(sqrt(3))#? - Socratic
2015年2月13日 · arctan( sqrt (3) ) = 60^@ or pi/3 radians If theta = arctan ( sqrt (3)) then tan (theta) = sqrt (3) by definition of tan-arctan relationship
How do you solve tanx=-sqrt3? - Socratic
2016年11月11日 · tanx=-sqrt3 x=tan^-1(-sqrt3) Radians: x=(2pi)/3, x=(5pi)/3 Degrees: x=120, x=300
How do you find the exact value of #tan^-1 (-sqrt3/3)#? - Socratic
2016年10月3日 · -pi/6 tan^-1(-sqrt3/3) tan^-1x means find the ANGLE that has a tangent of x The range of tan^-1 is -pi/2 to pi/2 -sqrt3/3 would fall in the fourth quadrant, so the value of tan^-1 is between -pi/2 and 0 and is a negative angle.
The relationship between tan (x) and square roots
2016年7月18日 · And realizing $3 * tan(30) = \sqrt 3$, I started investigating trig functions... And Taylor series... If this question has no "answer" at this moment in time, it might take "new mathematics" to find an answer, or existing maths may be able to solve it... Either way, I feel that there should be a way to represent these irrational numbers.