2009年4月23日 · you have (tan2x/1-tan 2 x) + tanx = 0 You find a common denominator of 1-tan 2 x this gives you: tan2x + (tanx)(1-tan 2 x) = 0 (this equation is all over '1-tan 2 x', but you can …

2020年5月5日 · First, draw a right triangle with legs 3 and 2. Then, by Pythagoras, the hypotenuse is √(3^2 + 2^2) = √13 ...

2014年7月3日 · tan2x=1-secx. We are supposed to find all solutions for each of the equations on the interval [0,2Π ...

2012年11月18日 · Michael B. Angel's answer is generally correct, if a bit confusing. I would have said it this way: think of (sin 2 x - sin 2 x cos 2 x) as (a - ab) where a=sin 2 x and b=cos 2 x.

2014年6月25日 · This yields cosx(3sin^2 x - cos^2 x) = 0. Set each factor to 0 and you get pi/2, 3pi/2, pi/6 and 7pi/6 as your answers.

2020年7月6日 · tanx=-3. use arctan on your calculator. tan is -3 at x=-71.565° 2x=-143.13° use your calculator to find the 3 values

2021年4月18日 · tan2x = sin2x/cos2x = 120/119. or sinx =5/13 x = sin^-1(5/13) = about 22.62 degrees. 2x =45.24. sin45.24 ...

2014年11月15日 · can u please help me to prove this. rhs=lhs. Follow • 2

2016年6月10日 · 1-tan^2(x) = 1 - (sin 2 x)/(cos 2 x) = [cos 2 x - sin 2 x]/cos 2 x = [cos 2x]/cos 2 x is a posibly 'simplified' version in that it has been boiled down to only cosines.

2019年3月21日 · Hi Maria, First, observe that sec^2(x) = 1 + tan^2 (x). Then substitute this for sec^2(x) in the formula: sec^2(x) + tan(x) = 1