2015年11月30日 · You are mistaken in your belief that max number for unsigned int is 65535. That hasn't been the case for most compilers since perhaps early days of windows 95 when …

2018年4月15日 · I would like to know if there is a particular reason to define the macro UINT_MAX as (2147483647 * 2U + 1U) and not directly its true value (4294967295U) in the …

2022年6月19日 · Just set the max using standard hexadecimal notation and then check it against whatever you need. 32-bits is 8 hexadecimals bytes, so it'd be like this: let myMax: UInt32 = …

2016年4月14日 · In C99, I include stdint.h and that gives me UINT32_MAX as well as uint32_t data type. However, in C++ the UINT32_MAX gets defined out. I can define …

2013年4月8日 · For C++ the value of UINT_MAX is also correct. – Pete Becker. Commented Apr 8, 2013 at 21:26. Add a ...

2019年2月12日 · But a better way to get the maximum value of type unsigned int is to use the UINT_MAX macro. You'll need. #include <limits.h> to make it visible. You can also compute …

2013年2月15日 · The standard mandates that UINT_MAX (and the maximal values of other unsigned integer types) is 2^N - 1, where N is the width of the type, so 10 is a bad example …

2017年6月29日 · Having typed "why is int16 limit 32,768" into google (after this question which would not have been in the results) the top result is "Why is the range of ints -32768 to 32767" …

2017年9月4日 · I've written the following program which seems to work well for what I need to do. However, I wonder why UINT_MAX is giving me -1 in the output (via printf()) and not …

2010年9月16日 · int: –2147483648 to 2147483647 uint: 0 to 4294967295 And for long (64 bit): long: -9223372036854775808 to 9223372036854775807 ulong: 0 to 18446744073709551615